A line with a slope of 1 passes through (9,7). what is it’s equation in slope intercept form
1 answer:
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Answer:
Step-by-step explanation:
Hello!
You need to test the hypothesis that "the average temperature for healthy adults is not equal to 98.6"
The variable of interest is
X: The body temperature of a healthy adult. (Fahrenheit)
And the parameter of interest is the population mean, μ.
The statistic hypotheses are:
H₀: μ = 98.6
H₁: μ ≠ 98.6
α:0.05
Assuming that the variable has a normal distribution you have to use a one-sample t-statistic for this test.
Attached to the answer is the data of body temperature of n=19 healthy adults. Since you didn't copy the raw data for your exercise I'll use this to answer the question.
Using the data the sample mean and standard deviation are:
X[bar]= 98.12
S= 0.69
This test is two-tailed, using the critical value approach, you have the rejection region divided into two tails determined by two critical values:
Decision rule:
If ≤ -1.965 or if
≥ 1.965, the decision is to reject the null hypothesis.
If -1.965 < < 1.965, the decision is to not reject the null hypothesis.
The calculated statistic is less than the lower critical value, the decision is to reject the null hypothesis.
Using a significance level of 5%, there is enough evidence to reject the null hypothesis. Then you can conclude that the true mean body temperature for healthy adults is not equal to the traditional 98.6F.
I hope this helps!
Answer:
Step-by-step explanation:
Given: △ABC, BC>AC, D∈ AC , CD=CB
To prove: m∠ABD is acute
Proof: In ΔABC, the angle opposite to side BC is ∠BAC and the angle opposite to side AC is ∠ABC.
Now, it is given that BC>AC, then ∠BAC>∠ABC.. (1)
In ΔBDC, using the exterior angle property,
∠ADB=∠DBC+∠BCD
∠ADB=∠DBC+∠BCA
⇒∠ADB>∠BAC (2)
From equation (1) and (2), we get
∠ADB>∠BAC
⇒∠ADB>∠ABC
⇒DB>AB
Hence, m∠ABD is acute
