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3 years ago

The table below shows a relationship between the variables x and y. Explain

Mathematics

1 answer:

larisa [96]3 years ago

6 0

There is a rule:

one input(x-value) can only have one output(y-value) in order to be a function.

So if one input has more than one output, it is not a function.

But if an output has more than one input, it is still a function.

This table does not represent a function because the inputs: 0, 1, 2,

have more than one output.

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Can someone tell me the answer for this please?

Tom [10]

4x+1+57=90
4x+58=90
4x=32
X=8

4 0

3 years ago

Apply the properties of exponents to rewrite each expression in the form kxn, where nn is an integer and x ≠0

professor190 [17]

Answer:

The expression will be $0.333x^{-2}$

Step-by-step explanation:

We have given expression $\frac{x^{-3}x^5}{3x^4}$

We know the property of exponent that when two function are divided then the power of exponent is subtracted and when there is multiplication of two function then exponent is added

So $\frac{x^{-3}x^5}{3x^4}=\frac{x^{2}}{3x^4}=0.333x^{-2}$

So the expression will be $0.333x^{-2}$

4 0

3 years ago

Evaluate the integral using integration by parts with the indicated choices of u and dv. (Use C for the constant of integration.

trasher [3.6K]

Answer:

$\frac{xe^{7x}}{7} + \frac{e^{7x}}{49}$

Step-by-step explanation:

Given the integral equation

$\int\limits{xe^{7x}} \, dx \\$

According to integration by part;

$\int\limits {u} \, dv = uv + \int\limits {v} \, du$

u = x, dv = e^7x

du/dx = 1

du = dx

$v = \int\limits {e^{7x}} \, dx \\v = e^7x/7$

Substitute the given values into the formula;

$\int\limits {xe^{7x}} \, dx = x(e^{7x}/7) + \int\limits ({e^{7x}/7}) \, dx\\\int\limits {xe^{7x}} \, dx = \frac{xe^{7x}}{7} + \frac{e^{7x}}{7*7} \\\int\limits {xe^{7x}} \, dx = \frac{xe^{7x}}{7} + \frac{e^{7x}}{49}$

3 0

3 years ago

Kamilah noticed that three different-sized boxes of the same cookies were on sale at a grocery store. The 425 g box was on sale

KengaRu [80]

Answer:

740 g box for $4.88, hope this helps

3 0

2 years ago

Savanna Smiles invested $5,000 for one year in a CD that earns interest at a rate of 3.5% compounded monthly. What is the intere

weeeeeb [17]

We are asked to solve for the interest during the year given that it is compounded monthly, we are given with the formula A = P(1+r)^n. The solution is shown below:
A = P (1+r)^n
A = $5,000 (1+ 3.5/12)^(12*1)
A = $5,000 (1.000292)^12
A = $5,177.84

5 0

3 years ago