Find Lim f(x) as x->0
for
f(x)=5x-8 ......x<0
f(x)=|-4-x|......x ≥ 0
Clearly
f(0)=|-4-0|=|-4|=4 exists.
The left-hand limit, as x-> 0- is f(0-)=5(0)-8=-8
The right hand limit, as x->0+ is f(0+)=|-4-0|=|-4|=4
Since the left and right limits do not both equal f(0), the limit does not exist.
The shaded areas add to 2/5 of the area of the circle, which is given by
A = πr²
Then the shaded area is ...
(2/5)A = (2/5)π(10 in)²
shaded area = 40π in²
Answer:
-4
Step-by-step explanation:
B is 4 units to the left of the origin.
A' is (-12, 6)
B' is (0,6)
C' is (3, -3)
D' is (-9, -3)
Hope this helps!
Answer:
$93.50
Step-by-step explanation:
81.30 x 1.15 = 93.50