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noname [10]
3 years ago
13

Sol

Mathematics
1 answer:
lisov135 [29]3 years ago
7 0

Answer:

Restaurant can purchase 6 adds when it want to spent total of $3600 and price of each add = $600.

Step-by-step explanation:

Given:

Amount restaurant can spend on advertising =$3600

Cost of 1 add = $600

To find:

Number of ads restaurant will be able to purchase. =?

Solution:

\text{{Number of adds restaurant can purchase}}= \frac{\text{{(Amount restaurant can spend on advertising )}}}{\text{{(Cost of 1 add)}}}

\text{{Number of adds restaurant can purchase}}=\frac{3600}{600}

Number of adds restaurant can purchase=6 adds

Hence restaurant can purcahse 6 adds when it want to spent total of $3600 and price of each add = $600.

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Barbara purchased a home entertainment center for $2,665 using an 18-month deferred payment plan with an interest rate of 24.36%
Andre45 [30]

Answer:

P = $ 144.99

Step-by-step explanation:

Given data:

cost of home entertainment center is $2665

duration of deferred payment plan is 18 month

interest rate is 24.36%

Total amount to be paid is = P(1+ \frac{R}{100})^t

                                          = 2665 (1+ \frac{24.36}{100})^1.5

A = 3695.88

From the information in the questioon this amount is to be paid in 3 year . Thus we have

Monthly payment is =

P = \frac{r(Pv)}{1 - (1+ r)^{-n}}

p = monthly payment

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r =rate per period = \frac{24.36}{12} = 0.020

n = number of period = 12\times 3 = 36

plugging all value in the above formula

P = \frac{0.020\times 3695.88}{1 - (1+0.020)^{-36}}

P = $ 144.99

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