Question

Find the equation of the line that passes through the points (-3,0) and (4,2). Using point slope formula

Answer 1

Answer:

$\large\boxed{y-0=\dfrac{2}{7}(x+3)}\\\downarrow\\\boxed{y=\dfrac{2}{7}x+\dfrac{6}{7}}$

Step-by-step explanation:

The point-slope form of an equation of a line:

$y-y_1=m(x-x_1)$

m - slopei

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

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We have the points (-3, 0) and (4, 2).

Substitute:

$m=\dfrac{2-0}{4-(-3)}=\dfrac{2}{7}$

Put the value of the slope and the coordinates of the point (-3, 0) to the equation:

$y-0=\dfrac{2}{7}(x-(-3))$

$y-0=\dfrac{2}{7}(x+3)$

Converto to the slope-intercept form (y = mx + b):

$y=\dfrac{2}{7}x+\dfrac{6}{7}$