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Verizon [17]
3 years ago
7

63+81= factor each expression

Mathematics
1 answer:
dlinn [17]3 years ago
4 0

 63

 81

24 4

the answer44

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Janeen wants to use the distributive property to find the value of 14⋅26+14⋅53. Which expression can she use?
murzikaleks [220]

Answer:

14(26+53)

Step-by-step explanation:

14*26 + 14*53 can be rewritten as 14(26+53).  The value of this expression is 14(79) = 1106.


5 0
3 years ago
Read 2 more answers
Will mark brainliest if right and you show your work!
Anna007 [38]

Answer:

(x - 5)(x + 8)

Step-by-step explanation:

Your equation is: x² + 3x - 40

1. Factor the quadratic

(a) Find two numbers that multiply to give -40 and add to give 3.

List the positive factors of 40: 1, 2, 4, 5, 8, 10, 20, 40

One of the numbers must be negative. Start with the numbers near the middle of the list.

By trial and error, you will find that +8 and -5 work:

-5 × 8 = -40 and -5+8 = 3

(b) Rewrite 3x as -5x + 8x

x² - 5x + 8x - 40

(c) Factor the first two and the last two terms

x(x - 5) + 8(x - 5)

(d) Separate the common factor

x² + 3x - 40  = (x - 5)(x + 8)

2. Using Desmos

You can plot the equation with Desmos.

You get a parabola with x-intercepts at x = -8 and x = 5.

These are the solutions to

x + 8 =0 and x - 5 = 0, so

x² + 3x - 40 =  (x+ 8)(x - 5)

6 0
3 years ago
3 points
stich3 [128]

Step-by-step explanation:

2x + 100 = 90

x = -5

Angle A = 45 - 5 = 40.

6 0
3 years ago
The ratio of the weight of Jennifer to that of her friend Laura is 6:11. Laura goes on a diet and loses 12kg and now the ratio o
Inessa05 [86]

Answer:

21kg

Step-by-step explanation:

We will do this.

11x - 12 = 7x

11x - 4x = 7x

4x = 12

4x/4 = 12/4

x = 3

3 x 7 = 21

Laura weighs 21 kg.

3 0
3 years ago
Give the first ten terms of the following sequences. You can assume that the sequences start with an index of 1. Logs are to bas
Vitek1552 [10]

Answer:

a)

a1 = log(1) = 0 (2⁰ = 1)

a2 = log(2) = 1 (2¹ = 2)

a3 = log(3) = ln(3)/ln(2) = 1.098/0.693 = 1.5849

a4 = log(4) = 2 (2² = 4)

a5 = log(5) = ln(5)/ln(2) = 1.610/0.693 = 2.322

a6 = log(6) = log(3*2) = log(3)+log(2) = 1.5849+1 = 2.5849 (here I use the property log(a*b) = log(a)+log(b)

a7 = log(7) = ln(7)/ln(2) = 1.9459/0.6932 = 2.807

a8 = log(8) = 3 (2³ = 8)

a9 = log(9) = log(3²) = 2*log(3) = 2*1.5849 = 3.1699 (I use the property log(a^k) = k*log(a) )

a10 = log(10) = log(2*5) = log(2)+log(5) = 1+ 2.322= 3.322

b) I can take the results of log n we previously computed above to calculate 2^log(n), however the idea of this exercise is to learn about the definition of log_2:

log(x) is the number L such that 2^L = x. Therefore 2^log(n) = n if we take the log in base 2. This means that

a1 = 1

a2 = 2

a3 = 3

a4 = 4

a5 = 5

a6 = 6

a7 = 7

a8 = 8

a9 = 9

a10 = 10

I hope this works for you!!

3 0
3 years ago
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