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4 years ago

Evaluate the expression when a = 2 and b = 4. 6a – 2b + 5 A. 43 B. 1 C. 45 D. 9

Mathematics

1 answer:

tamaranim1 [39]4 years ago

6 0

Hi there!
6(2) -2(4) +5
12-8+5
So D would be correct.

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A particle moves on the hyperbola xy=18 for time t≥0 seconds. At a certain instant, y=6 and dydt=8. What is x that this instant?

professor190 [17]

Answer:

The value of x at this instant is 3.

Step-by-step explanation:

Let $x\cdot y = 18$ , we get an additional equation by implicit differentiation:

$x\cdot \frac{dy}{dt}+y\cdot \frac{dx}{dt} = 0$ (1)

From the first equation we find that:

$x = \frac{18}{y}$ (2)

By applying (2) in (1), we get the resulting expression:

$\frac{18}{y}\cdot \frac{dy}{dt}+y\cdot \frac{dx}{dt} = 0$ (3)

$y\cdot \frac{dx}{dt}=-\frac{18}{y}\cdot \frac{dy}{dt}$

$\frac{dx}{dt} = -\frac{18}{y^{2}} \cdot \frac{dy}{dt}$

If we know that $y = 6$ and $\frac{dy}{dt} = 8$ , then the first derivative of x in time is:

$\frac{dx}{dt} = -\frac{18}{6^{2}} \cdot (8)$

$\frac{dx}{dt} = -4$

From (1) we determine the value of x at this instant:

$x\cdot \frac{dy}{dt} = -y\cdot \frac{dx}{dt}$

$x = -y\cdot \left(\frac{\frac{dx}{dt} }{\frac{dy}{dt} } \right)$

$x = -6\cdot \left(\frac{-4}{8} \right)$

$x = 3$

The value of x at this instant is 3.

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3 years ago

If y=3x^3-2x and (dx)/(dy) = 3, find (dy)/(dt) when x=-2

lesya692 [45]

Answer:

dy/dx = 9x²+2

dy = (9x²+2) dx

dy/dt = (9x²+2) dx/dt

if x = 2 and dx/dt=5 then

dy/dt = (9*2²+2)*5 = 38*5 = 190

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The answer is A

Step-by-step explanation:

Just trust me the answer is A lol.

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