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4 years ago

Evaluate the expression when a = 2 and b = 4. 6a – 2b + 5 A. 43 B. 1 C. 45 D. 9

Mathematics

1 answer:

tamaranim1 [39]4 years ago

6 0

Hi there!
6(2) -2(4) +5
12-8+5
So D would be correct.

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There’s no actual question just this picture & multiple choices , please help .

kupik [55]

Answer:

Step-by-step explanation:

There is a right angle formed, hence this triangle is a right-angled triangle.

Using Pythagoras Theorem,

$a^2+b^2=c^2$

$16^2+b^2=20^2$

$256+b^2=400$

$b^2=400-256=144$

$b=12$

The missing length is 12

4 0

2 years ago

We want to factor the following expression: (x 3)^2 14(x 3) 49(x 3) 2 14(x 3) 49(, x, plus, 3, ), squared, plus, 14, (, x, plus,

Nesterboy [21]

Answer:

$U = x$

$V=10$

Step-by-step explanation:

Given

$(x +3)^2 + 14(x + 3) + 49 = (U + V)^2$

Required

Find U and V

We have:

$(x +3)^2 + 14(x + 3) + 49 = (U + V)^2$

Expand

$x^2 + 6x + 9 + 14x + 42 + 49 = (U + V)^2$

Collect like terms

$x^2 + 6x + 14x + 9 + 42 + 49 = (U + V)^2$

$x^2 + 20x + 100 = (U + V)^2$

Expand

$x^2 + 10x + 10x + 100 = (U + V)^2$

Group

$[x^2 + 10x] + [10x + 100] = (U + V)^2$

Factorize each group

$x[x + 10] + 10[x + 10] = (U + V)^2$

Factor out x + 10

$[x + 10][x + 10] = (U + V)^2$

So, we have:

$[x + 10]^2 = (U + V)^2$

By comparison

$U = x$

$V=10$

7 0

3 years ago

What is the answer to -17x=-204

Elenna [48]

The answer for this problem is x=12.

7 0

3 years ago

The difference of the square of a number and 24 is equal to 5 times that number. Find the negative solution.

SVEN [57.7K]

Answer:

n = -3

Step-by-step explanation:

The difference of the square of a number and 24 is equal to 5 times that number. Find the negative solution.

I'm going to call the number "n."

n² - 24 = 5n subtract 5n from both sides to get the equation equal to zero

- 5n -5n

n² - 5n - 24 = 0 factor the trinomial into the multiplicatin of two binomials

we need factors (numbers that multiply) to -24 that add up to

-5. The only factors for -24 that will add up to -5 are -8 and 3.

(n-8)(n+3) = 0 set each binomial equal to zero and solve for n

n-8 = 0 or n+3 = 0

+8 +8 -3 -3

n = 8 or n = -3 n = -3 is the negative solution

3 0

3 years ago

Simplify (8x^2 − 1 + 2x^3) − (7x^3 − 3x^2 + 1).

DENIUS [597]

8x^2-1+2x^3-7x^3+3x^2-1

-5x^3+11x^2-2

8 0

3 years ago