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solmaris [256]
3 years ago
6

Start 14 . skip count by tens to 54 . do the ones digits change ? explain​

Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
7 0

Answer:

No because if you count by tens your basically only adding 1 each time to the tens place. 14, 24, 34, 44, 54. Each time you count by ten the only digit that changes is the tens place.

Step-by-step explanation:

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The graph of the parent function f(x) = x3 is translated such that the resulting graph can be represented by the function g(x) =
kirill115 [55]

Answer:

Translated 1 to the right and up one

Step-by-step explanation:

When the number is inside the parenthesis with x, that value represents a horizontal shift. because the original equation is (x-h), the opposite sign of the x value must be taken. so in this case the x value would be +1 because that is the opposite of -1, which means the function is being moved one to the right. when the number is being added to the outiside of the parenthesis, then you take that value for the vertical translations of the graph. because the original equation is (x-h)+k, then in this case there would be a vertical shift up by 1

8 0
3 years ago
Read 2 more answers
A rectangular prism has a length of 3 feet, a height of 7 feet, and a width of 14 feet.
MA_775_DIABLO [31]

Answer:

294 cubic ft.

Step-by-step explanation:

All you do is just multiply the length, width, and height!

3 × 14 × 7 = 294

hopefully this helped :3

5 0
3 years ago
Read 2 more answers
72
Zigmanuir [339]

Answer:

Ai. Arithmetic sequence

Aii. Tn = 5 + 7n

Bi. Geometric

Bii. Tn = 8 × 2ⁿ¯¹

Step-by-step explanation:

To successfully answer the questions given above, note the following:

1. If the sequence is Arithmetic, then:

2nd – 1st = 3rd – 2nd = common difference (d)

2. If the sequence is geometric, then,

2nd / 1st = 3rd / 2nd = common ratio (r)

3. A sequence can not be arithmetic geometric at the same time.

4. The nth term of arithmetic sequence is:

Tn = a + (n – 1)d

5. The nth term of geometric sequence is:

Tn = arⁿ¯¹

A. Sequence => 12, 19, 26

i. Determination of the type of sequence.

We'll begin by calculating the common difference

1st term = 12

2nd term = 19

3rd term = 26

Common difference (d) = 2nd – 1st

d = 19 – 12 = 7

OR

d = 3rd – 2nd

d = 26 – 19 = 7

Since a common difference exist in the sequence, the sequence is arithmetic sequence.

ii. Determination of the nth term.

Common difference (d) = 7

1st term (a) = 12

nth term (Tn) =?

Tn = a + (n – 1)d

Tn = 12 + (n – 1)7

Tn = 12 + 7n – 7

Tn = 5 + 7n

B. Sequence => 8, 16, 32

Bi. Determination of the type of sequence.

Let us begin by calculating the common ratio.

1st term = 8

2nd term = 16

3rd term = 32

Common ratio (r) = 2nd / 1st

r = 16 / 8

r = 2

OR

r = 3rd / 2nd

r = 32 / 16

r = 2

Since a common ratio exist in the sequence, the sequence is geometric.

Bii. Determination of the nth term.

Common ratio(r) = 2

1st term (a) = 8

nth term =?

Tn = arⁿ¯¹

Tn = 8 × 2ⁿ¯¹

8 0
2 years ago
What is the slope of this graph?
larisa [96]
Since the slope is falling, instead of rising, it would be negative. 

Now, on the line, I plotted (0, 2) and (-2, 10).

You would now plug this into the rise/run formula. 
The formula is \frac{y2 - y1}{x2 - x1}

The equation would become, 
\frac{10 - 2}{-2 - 0} = \frac{8}{-2} = -4

I believe the answer would be -4. 

I hope this helps!

6 0
3 years ago
A lock has a three number code made up of 17 numbers if none of the numbers are allowed to repeat how many different ways can yo
Marrrta [24]

Answer:

680

Step-by-step explanation:

Use the binomial coefficient where you choose k=3 numbers out of n=17 possible numbers and find the total amount of combinations since order does not matter:

\displaystyle \binom{n}{k}=\frac{n!}{k!(n-k)!}\\ \\\binom{17}{3}=\frac{17!}{3!(17-3)!}\\\\\binom{17}{3}=\frac{17!}{3!(14)!}\\\\\binom{17}{3}=\frac{17*16*15}{3*2*1}\\\\\binom{17}{3}=680

Thus, you can make 680 three-non-repeating-number codes

8 0
2 years ago
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