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Ne4ueva [31]
3 years ago
7

Terbium-160 has a half-life of about 72 days. After 396 days, about how many milligrams of a 220 mg sample will remain?

Mathematics
2 answers:
liberstina [14]3 years ago
8 0
C....................
garik1379 [7]3 years ago
3 0

Answer:

Option A = 5 mg  

Step-by-step explanation:

Given : Terbium-160 has a half-life of about 72 days.

To find : After 396 days, about how many milligrams of a 220 mg sample will remain?

Solution :

We have given the Terbium-160 has a half-life of about 72 days.  

We can represent the situation with an exponential function,

A_t = A_0(0.5)^{\frac{t}{n}}

Where,

A_t is the amount at any time t,

A_0=220 is the original amount,

n=72 is the half-life

t=365 number of days

Substituting all the values,

A_t =220(0.5)^{\frac{396}{72}}

A_t =220(0.5)^{5.5}

A_t =220(0.022)

A_t =4.84

Approximately 4.84=5 mg

Therefore, Option A is correct.  

After 396 days, there will only be 5 mg of Terbium-160.                        

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Answer:

1.967 × 10⁻¹¹

Step-by-step explanation:

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f(12) = 12 e⁻⁶⁰ = 1.051 × 10⁻²⁵

P(17|12) = (2.067 × 10⁻³⁶)/(1.051 × 10⁻²⁵)

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8 0
3 years ago
Humphrey needs to mail a package. He weighs it at home as 20.2 ounces. When he gets to the post office, the clerk weighs it at 1
Scrat [10]

Answer:

7.92%

Step-by-step explanation:

Given the following

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Weight of the package at the office = 18.6ounces

Decrement = 20.2 - 18.6

percentage error = decrement/wt at home * 100

percentage error = 1.6/20.2* 100

percentage error = 160/20.2

percentage error = 7.92

HEnce  the percent error in the weight of the package is 7.92%

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3 years ago
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Papessa [141]

Answer:

C=78.28^{\circ \:}

Step-by-step explanation:

We are given a triangle

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a=12

b=8

c=13

Since, c is largest among them

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we can find angle C

we can use law of cosine formula

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cos(C)=\frac{12^2+8^2-13^2}{2\times 12\times 8}

cos(C)=\frac{13}{64}

now, we can find angle

we get

C=78.28^{\circ \:}

5 0
3 years ago
A bee beats its wings 250 times each second what is the average time for a single beat of a bee's wing
eduard
No. Of times bee beats in 1 sec=250
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Frst find how many times bee beats in 1 min.
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Step-by-step explanation:

FÓRMULA:

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b = 144 m^{2}/8 m = 18 m

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3 years ago
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