Answer:
Option A = 5 mg
Step-by-step explanation:
Given : Terbium-160 has a half-life of about 72 days.
To find : After 396 days, about how many milligrams of a 220 mg sample will remain?
Solution :
We have given the Terbium-160 has a half-life of about 72 days.
We can represent the situation with an exponential function,
![A_t = A_0(0.5)^{\frac{t}{n}}](https://tex.z-dn.net/?f=A_t%20%3D%20A_0%280.5%29%5E%7B%5Cfrac%7Bt%7D%7Bn%7D%7D)
Where,
is the amount at any time t,
is the original amount,
n=72 is the half-life
t=365 number of days
Substituting all the values,
![A_t =220(0.5)^{\frac{396}{72}}](https://tex.z-dn.net/?f=A_t%20%3D220%280.5%29%5E%7B%5Cfrac%7B396%7D%7B72%7D%7D)
![A_t =220(0.5)^{5.5}](https://tex.z-dn.net/?f=A_t%20%3D220%280.5%29%5E%7B5.5%7D)
![A_t =220(0.022)](https://tex.z-dn.net/?f=A_t%20%3D220%280.022%29)
![A_t =4.84](https://tex.z-dn.net/?f=A_t%20%3D4.84)
Approximately 4.84=5 mg
Therefore, Option A is correct.
After 396 days, there will only be 5 mg of Terbium-160.