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3 years ago

5

Factor 18 out of 18x−498 ( THIS IS 7th GRADE MATH BTWWWW <3)

1 answer:

Svetradugi [14.3K]3 years ago

5 0

Use pemdas it helps

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A sphere has a volume of Vequals=3600 in cubedin3. Find its surface area.

Mice21 [21]

$\bf \textit{volume of a sphere}\\\\
V=\cfrac{4}{3}\pi r^3\qquad 
\begin{cases}
r=radius\\
------\\
V=3600
\end{cases}\implies 3600=\cfrac{4}{3}\pi r^3
\\\\\\
3600=\cfrac{4\pi r^3}{3}\implies \sqrt[3]{\cfrac{3\cdot 3600}{4\pi }}=\boxed{r}\\\\
-----------------------------\\\\
\textit{surface area of a sphere}\\\\
S=4\pi r^2\implies S=4\pi \left(\boxed{\sqrt[3]{\cfrac{3\cdot 3600}{4\pi }}} \right)^2$

simplify away

8 0

3 years ago

PLEASEEEE I need help :(

S_A_V [24]

Don’t mind my math homework- But ya the answer would be -1/3. You’re welcome I got your back :)

4 0

2 years ago

Sians room is in the shape of a square. It’s area is 121 square feet . How long is one side of sian’s room ?

Sladkaya [172]

11. Square root of 121

5 0

2 years ago

Solve for j in the literal equation h-4/j

igor_vitrenko [27]

Answer:

$h - 4 \div j = 0 \\ - 4 \div j = - h \\ 4 \div j = h \\ j = 4 \div h$

3 0

3 years ago

Find the cos A and tan B to four decimal places. URGENT

Nikolay [14]

cos A is 0.8511 and tan B is 1.6

Step-by-step explanation:

Find the 3rd length or the hypotenuse.

<u>Pythagoras theorem</u>

$hypotenuse^{2}$ = $adjacent^{2}$ + $opposite^{2}$

$hypotenuse^{2}$ = $8^{2}$ + $5^{2}$

$hypotenuse^{2}$ = 64 + 25

hypotenuse = $\sqrt{89}$

hypotenuse = 9.4

a) Cos A

<u>Data:</u>

Adjacent = 8

Hypotenuse = 9.4

<u>Formula:</u>

Cos (Angle) = $\frac{adjacent}{hypotenuse}$

Cos A = $\frac{8}{9.4}$

Cos A = 0.8511

A = $cos^{-1}$ (0.8511)

A = 31.7°

b) Tan B

<u>Data: </u>

Opposite = 8

Adjacent = 5

<u>Formula:</u>

Tan (Angle) = $\frac{opposite}{adjacent}$

Tan B = $\frac{8}{5}$

Tan B = 1.6

B = $cos^{-1}$ (1.6)

B = 58°

Therefore, cos A is 0.8511 and tan B is 1.6.

Keyword: cos, tan

Learn more about cos at

#LearnwithBrainly

3 0

2 years ago