Answer:
30 mph
Step-by-step explanation:
Let d = distance (in miles)
Let t = time (in hours)
Let v = average speed driving <u>to</u> the airport (in mph)
⇒ v + 15 = average speed driving <u>from</u> the airport (in mph)
Using: distance = speed x time

Create two equations for the journey to and from the airport, given that the distance one way is 18 miles:

We are told that the total driving time is 1 hour, so the sum of these expressions equals 1 hour:

Now all we have to do is solve the equation for v:







As v is positive, v = 30 only
So the average speed driving to the airport was 30 mph
(and the average speed driving from the airport was 45 mph)
Answer:
B
Step-by-step explanation:
∠ BSR + ∠ TSB = ∠ TSR , substitute values
2x + 17 + 5x + 15 = 102 , that is
7x + 32 = 102 ( subtract 32 from both sides )
7x = 70 ( divide both sides by 7 )
x = 10 → B
Answer:
-2
Step-by-step explanation:
1. 0.8
2. 3.87298
3. ?
4. ?
5. ?
6. 5
7. True
8. ?
9.
Answer:
Step-by-step explanation:
Use Pythagorean theorem
Base² + altitude² = hypotenuse²
Base² + 7² = 20²
Base² + 49 = 400
Base² = 400 - 49 = 351
Base = √351 = 18.73 = 18.7 mm