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2 years ago

11

This graph models the number of teachers assigned to a school, as determined by the number of students. What is the constant of

proportionality?
1/25
1/20
1/15
1/10

2 answers:

alisha [4.7K]2 years ago

8 0

(60,4)(120,8)
slope = (8 - 4) / (120 - 60) = 4/60 = 1/15 <== the constant of proportionality is the slope

Ilya [14]2 years ago

4 0

Answer:

The correct option is 3.

Step-by-step explanation:

Form the given figure it is noticed that the line is passing through the points (60,4) and (120,8).

$y\propto x$

$y=kx$

Where, k is the constant of proportionality or slope.

The slope of a line is defined as

$k=\frac{y_2-y_1}{x_2-x_1}$

$k=\frac{8-4}{120-60}$

$k=\frac{4}{60}$

$k=\frac{1}{15}$

Therefore option 3 is correct.

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1 year ago

Plz help<br> and explain

vovikov84 [41]

To solve this problem, we need to first find the dimensions of the side of the blue and purple squares.

We're given that the purple (smaller) square has a side length of x inches.
We are also given that the blue band has a width of 5 inches.
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The net area of the band is therefore the difference of the area of the blue square and the purple square, namely take out the area of the purple square from the blue.

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8 0

3 years ago

You have 20 bucks in your pocket.

diamong [38]

Answer:

the answer would be $45.55

<3

Step-by-step explanation:

20$ + $50.00 = $70

$70 - $6.95 = $64.5

$64.5 - $9.95 = $54.55

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5 0

2 years ago

The sum of the diagonals of a rhombus is 5√2.

Alex

Greetings!
Let ABCD be a rhombus
AC + BD = 5√2 cm

Area of ABCD = Ar△ABD + Ar △BCD
$= \frac{1}{2} \times BD \times AO + \frac{1}{2} \times BD \times OC$
$= \frac{1}{2} BD (AO + OC)$
$\frac{1}{2} BD \times AC$

$So, \frac{ BD \times AC}{2} = 4 \: cm {}^{2}$
$BD \times AC = 8$
$Now, AC + \: BD = 5 \sqrt{2}$

Squaring both sides, we get
$AC {}^{2} + BD {}^{2} + 2 AC.BD =50$
$AC {}^{2} + BD {}^{2} + 2 \times 8 = 50$
$AC {}^{2} + BD {}^{2} = 50 - 16$
$AC {}^{2} + BD {}^{2} = 34$

In △AOB, we have
$OA {}^{2} + OB {}^{2} =AB {}^{2}$
$( \frac{ AC }{2} ) {}^{2} + ( \frac{ BD}{2} ) {}^{2} = AB {}^{2}$
$\frac{ AC {}^{2} } {4} + \frac{ BD {}^{2} }{4} = AB {}^{2}$
$AC {}^{2} + BD {}^{2} = 4 AB {}^{2}$
$34 = 4 AB {}^{2}$

Square rooting both sides
$\sqrt{34} = 2 AB$
$Perimeter = 4 \: AB \\ = 2 \times 2 \: AB \\ = 2 \: \times \sqrt{34 } \\ = 2 \sqrt{34 \: } units$ .

Hope it helps!

7 0

3 years ago