Answer:
It's y = (5)(0.2)^x
_____________
Step-by-step explanation:
Exponential functions have a standard form of ab^x
Where a is the starting value, and b is the exponential growth or decay.
Because the numbers are getting smaller and smaller, it is a decay so b must be less than one.
We can eliminate the first choice because when x is 1, y is 1. If this where the equation we would get (5) (1/2) ^ 1 = 5 × 1/2 = 2.5 ≠ 1.
So the answer must be the second choice.
Answer:

Step-by-step explanation:
The PDF of X is
The PDF of Y is
The means of X and Y are respectively,
so we can see that the larger the parameter, the smaller the mean. Hence the PDF of Z = min(X, Y) is an exponential with the largest parameter of the two.
Therefore, the PDF of Z is
there are two expressions that can represent the length of the rectangle, these two expressions are:
L = x
or
L = (4x + 12)
<h3>
Which expression could represent the length of the rectangle?</h3>
Remember that for a rectangle of length L and width W, the area is given by:
A = L*W
In this case, we know that the area is:

We can factorize that expression into:

So there are two expressions that can represent the length of the rectangle, these two expressions are:
L = x
or
L = (4x + 12)
If you want to learn more about rectangles:
brainly.com/question/17297081
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Answer:
The probability that there are 2 or more fraudulent online retail orders in the sample is 0.483.
Step-by-step explanation:
We can model this with a binomial random variable, with sample size n=20 and probability of success p=0.08.
The probability of k online retail orders that turn out to be fraudulent in the sample is:

We have to calculate the probability that 2 or more online retail orders that turn out to be fraudulent. This can be calculated as:
![P(x\geq2)=1-[P(x=0)+P(x=1)]\\\\\\P(x=0)=\dbinom{20}{0}\cdot0.08^{0}\cdot0.92^{20}=1\cdot1\cdot0.189=0.189\\\\\\P(x=1)=\dbinom{20}{1}\cdot0.08^{1}\cdot0.92^{19}=20\cdot0.08\cdot0.205=0.328\\\\\\\\P(x\geq2)=1-[0.189+0.328]\\\\P(x\geq2)=1-0.517=0.483](https://tex.z-dn.net/?f=P%28x%5Cgeq2%29%3D1-%5BP%28x%3D0%29%2BP%28x%3D1%29%5D%5C%5C%5C%5C%5C%5CP%28x%3D0%29%3D%5Cdbinom%7B20%7D%7B0%7D%5Ccdot0.08%5E%7B0%7D%5Ccdot0.92%5E%7B20%7D%3D1%5Ccdot1%5Ccdot0.189%3D0.189%5C%5C%5C%5C%5C%5CP%28x%3D1%29%3D%5Cdbinom%7B20%7D%7B1%7D%5Ccdot0.08%5E%7B1%7D%5Ccdot0.92%5E%7B19%7D%3D20%5Ccdot0.08%5Ccdot0.205%3D0.328%5C%5C%5C%5C%5C%5C%5C%5CP%28x%5Cgeq2%29%3D1-%5B0.189%2B0.328%5D%5C%5C%5C%5CP%28x%5Cgeq2%29%3D1-0.517%3D0.483)
The probability that there are 2 or more fraudulent online retail orders in the sample is 0.483.