Question

Find each product with work (3g + 2)(3g–2)​

Answer 1

Answer:

See explanation!

Step-by-step explanation:

Due to the way the question is expressed we will assume that it means to find the product of this expression (thus simplify or factor our the equation).

So let us solve as following:

$(3g+2)(3g-2)=0\\\\(3g)(3g)+(3g)(-2)+(2)(3g)+(2)(-2)=0\\\\9g^2-6g+6g-4=0\\\\9g^2-4=0\\9g^2=4\\\\g^2=\frac{4}{9}\\ \\g=(+/-)\sqrt{\frac{4}{9} } \\\\g=(+/-)\frac{2}{3}$

So we have factored our the expression and solve for the values of $g$ which since its squared, the solution can be either positive or negative. Thus

$g=\frac{2}{3}$ and $g=-\frac{2}{3}$