Answer:
Therefore the volume of the box is 13824 in³
Step-by-step explanation:
Given:
A spherical ball with is packaged in a box that is in the shape of a cube.
Volume of ball = 2304π in³.
Let 'r' be the radius of sphere
To Find:
Volume of Cube = ?
Solution:
Volume of sphere is given by
Substituting the values we get
Now we know that diameter is given by
it is given that,
The edge length of the box is equal to the diameter of the ball.
Therefore the length of cube = 24 in
Now the volume of the cube is given by
substituting the values we get
Therefore the volume of the box is 13824 in³
<span>A=P<span>e^<span>rt</span></span></span>
P = 100
r = .035
t = 8
So we have
<span>A=100<span>e^<span>8×.035</span></span></span>
<span>A=100<span>e^.28</span></span>
<span><span>A=132.31</span></span>
Is there like a picture or something?
Answer:
A = 2
Step-by-step explanation:
When there are no solutions for x, both sides x cancel leaving an equation with two distinct numbers equal to each other (e.g. 6 = 0). Therefore, we must find a number A for which that happens.
Lets first simplify the equation, 3Ax - 24 = 5x - 9 + x = 6x - 9.
We want to cancel out the 6x on both sides. This happens when the left side also has 6x, so 3Ax = 6x -> A = 2.
Testing out this works, we get:
6x - 24 = 6x - 9 -> -24 = -9 (which isn’t true)
We get no solutions, which is what we are looking for! Therefore, A = 2 must be our answer!
I hope this helps! :)
Answer:
-200
Step-by-step explanation:
ATQ, a+11d=-13 and a+a+d+a+2d+a+3d=24, 4a+6d=24. Solving this, we get a=9 and d=-2. Sum of the first 20 terms is 10*(18+(19)*(-2))=-200
