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jek_recluse [69]
3 years ago
7

Sam evaluated the expression x2y for x = 7 and y = 9. He got a value of 49. which of the follwing statements is correct

Mathematics
1 answer:
Marrrta [24]3 years ago
7 0
<span>B. sam forgot to multiply. 
 The correct answer is
</span> x^2*y=(7^<span>2)*(9)=49*9=441 </span> 
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Which number is an integer, a whole number, and a counting (natural) number? a) 0 b) -1 c) 15 d) 0.5
velikii [3]
C. 15

-1 is not a natural number so B is not your answer

0.5 is not a whole number so D is not your answer

0 is not a natural number so A is not your answer
7 0
2 years ago
A new car is purchased for $17,000 and over time its value depreciates by one half every 3 years. What is the value of the car 1
Jet001 [13]

Answer:

The answer is "$238".

Step-by-step explanation:

Current worth= \$ 17,000

depreciates by \frac{1}{2} in 3 years.

time=  19 years

depreciates rate=?

Using formula:

\to \text{Worth=  Current worth}(1- \frac{\text{depreciates rate}}{100})^{time}

\to A_t=A_0(1-\frac{r}{100})^t

calculates depreciate value in 3 year = \frac{1}{2} \times 17,000

                                                              = 8,500

so,

A_t=8,500\\\\A_0=17,000\\\\t=3\ years

\to A_t=A_0(1-\frac{r}{100})^t\\\\\to 8,500= 17,000(1-\frac{r}{100})^3\\\\\to \frac{8,500}{17,000}= (1-\frac{r}{100})^3\\\\\to \frac{1}{2}= (1-\frac{r}{100})^3\\\\\to (\frac{1}{2})^{\frac{1}{3}}= (1-\frac{r}{100})\\\\\to 0.793700526 = (1-\frac{r}{100})\\\\\to \frac{r}{100} = (1-0.793700526)\\\\\to \frac{r}{100} = (1-0.8)\\\\\to r= 0.2 \times 100 \\\\\to r= 20 \%

depreciates rate= 20%

\to \text{Worth=  Current worth}(1- \frac{\text{depreciates rate}}{100})^{time}

= \$ 17,000 (1- \frac{20}{100})^{19}\\\\= \$ 17,000 (1-0.2)^{19}\\\\= \$ 17,000 (0.8)^{19}\\\\= \$ 17,000 \times 0.014\\\\= \$ 238

4 0
2 years ago
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Danny's truck has a fuel tank with a capacity of 20 gallons of gas. The truck averages 17 miles per gallon of gas. The function
Fittoniya [83]

For this case we have the following function:

M (g) = 17g

Where,

g: number of gallons of gas

M (g): number of miles that Danny's truck travels

We know that the maximum capacity is 20 gallons of gas.

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M (20) = 17 (20)

M (20) = 340

Thus, the domain of the function is:

0 \leq g \leq 20

The range of the function is:

0 \leq M(g) \leq 340

Answer:

A domain and range that are reasonable for the function are:

D. D: 0 ≤ g ≤ 20

R: 0 ≤ M (g) ≤ 340

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