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Leno4ka [110]
3 years ago
12

A line has equation y=x−5. The line is shifted 3 units to the left and 1 unit up. Which points are on the graph of the line afte

r these 2 transformations are applied?

Mathematics
1 answer:
Katyanochek1 [597]3 years ago
5 0
This is one way to do it

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90 points!!
Svetllana [295]

Answer:

1) 2w + 2(3w) \leq 112

2) 850w > 300w + 7500

3) The greatest age that Sue could be is 7.

4) The smaller of the two integers is 92.

5) Don needs to earn at least 244 points in the fourth game.

Step-by-step explanation:

1) An rectangle has 2 dimensions: width(w) and length(l)

The perimeter P is:

P = 2w + 2l

The problem states that the length of a rectangle is three times its width. So l = 3w and:

P = 2w + 2(3w)

The perimeter of the rectangle is at most 112 cm. It means that the perimeter can be 112, so the equal sign enters the inequality. So

2w + 2(3w) \leq 112

2)

The problem states that he earns $850 per week in sales. His earnings is modeled by the following equation:

E = 850*w, in which w is the number of weeks.

The problem also states that he spent $7500 to obtain his merchandise, and it costs him $300 per week for general expenses. So his expenses can be modeled by the following equation

C = 300*w + 7500, in which w is also the number of weeks.

He will make a profit when his earnings are bigger than his expenses, so: When they are equal, there is no profit, so the equal sign does not enter the inequality.

E > C

850w > 300w + 7500

3)

I am going to call Jenny's age x and Sue's age y.

The problem states that Jenny is eight years older than twice her cousin Sue’s age. So

x = 8 + 2y.

The sum of their ages is less than 32, so:

x + y < 32

8 + 2y + y < 32

3y < 24

y < \frac{24}{3}

y < 8

Sue's age has to be less than 8, so the greatest age that Sue could be is 7.

4)

The sum of two consecutive integers is at least 185.

There are two integers with sum of 185, so:

x + y = 185

They are consecutive so:

x = y + 1

Replacing in the sum equation:

y + 1 + y = 185

2y = 184

y = \frac{184}{2}

y = 92

The smaller of the two integers is 92.

5)

The average is the sum of all the scores divided by the number of games. So:

225 = \frac{192 + 214 + 250 + x}{4}

656 + x = 900

x = 900 - 656

x = 244

Don needs to earn at least 244 points in the fourth game.

8 0
3 years ago
I need help finding Sin B, Cos B, and Tan A for a geometry problem. please help meee
Scilla [17]

Answer:

Sin B = 5/13

Cos B = 12/13

tan A = 12/5

Step-by-step explanation:

Sin B = opposite side/ hypotenuse

Sin B = 5/13

Cos B = adjacent side / hypotenuse

         = 12/13

tan A = opposite side /adjacent side

          = 12/5

6 0
3 years ago
A1<br> B2<br> C3<br> D4<br> what is it
Sonja [21]
I believe four is the right answer to the problem
5 0
3 years ago
What is 3 to the power of -4 as a fraction?
ivolga24 [154]
The answer is 1/81 :)
3 0
3 years ago
Read 2 more answers
A square grassy field is watered by 4 sprinklers. The sprinklers spray water in a circular pattern, as shown above. If the field
enot [183]
The answer is (3600 - 900π) ft²

Step 1. Find the radius r of circles.
Step 2. Find the area of the portion of the field that will be watered by the sprinklers (A1)
Step 3. Find the total area of the field (A2)
Step 4. Find the area of the portion of the field that will not be watered by the sprinklers (A)

Step 1. Find the radius r of circles
r = ?
According to the image, radius of a square is one fourth of the field side length:
r = s/4
s = 60 ft
r = 60/4 = 15 ft

Step 2. Find the area of the portion of the field that will be watered by the sprinklers.
The area of the field that will be watered by the sprinklers (A1) is actually total area of 4 circles with radius 15 ft.
Since the area of a circle is π r², then A1 is:
A1 = 4 * π r² = 4 * π * 15² = 900π ft²

Step 3. Find the total area of the field (A2)
The field is actually a square with side s = 60 ft.
A2 = s² = 60² = 3600 ft²

Step 4. Find the area of the portion of the field that will not be watered by the sprinklers (A).
To get the area of the portion of the field that will not be watered by the sprinklers (A) we need to subtract the area of 4 circles from the total area:
A = A2 - A1
A = (3600 - 900π) ft²
5 0
3 years ago
Read 2 more answers
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