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yaroslaw [1]
3 years ago
14

Write an expression in factored form that is equivalent to the given expression. 1/2x + 4 . can u also tell how you solved it ?

Mathematics
1 answer:
Rufina [12.5K]3 years ago
5 0
2 ways: Easy and hard
Hard=A
Easy=B
A: 1/2x+4 work from there so we do fun stuff with it make something that can be simplified so 1/2x+4 times (2/2)=x+8 now square the whole thing and put the result in a square root thingie (x+8)^2=x^2+16x+64 \sqrt{x^2+16x+64} multiply the whole thing by 4/4 and put \sqrt{16} [\tex] on top so then 
[tex] \sqrt{x^2+16x+64} times \frac{ \sqrt{16} }{4}=\frac{\sqrt{(16)(x^2+16x+64)}}{4}=\frac{ \sqrt{16x^2+256x+1024} }{4} to solve it, factor out the 16 in the square root and then square root 16 to get 4 then it will be (4 times square root of equation)/4=square root of equatio factor square root of equation and square root it and get x+8 divide by 2 to get 1/2x+4


B: 1/2x+4
put stuff that cancels out
1/2x+3x-3x+4+56-56
move them around
3 and 1/2x-3x+60-56
or
2x-3x+1 and 1/2x+30-20+30-36
then just add like terms to solve

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Step-by-step explanation:

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Xelga [282]
The correct answer is -4.
5 0
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Read 2 more answers
Plz ans with steps... Thx!!
Ganezh [65]

Answer:

16

Step-by-step explanation:

Let the 1st part of your answer be x , so the 2nd part will be 40-x . From the given information, we can write the equation: (1/4)x = (3/8) × (40-x) . We can simplify this into (1/4)x = (120-3x)/8 ; 8x = 480-12x ; 8x+12x = 480 ; 20x = 480 ; x = 480/20; x = 24

Therefore, the 1st part = 24

Plug this into your 40-x equation to get: 40 - 24 = 16

3 0
3 years ago
CosA.cos2A.cos4A=sin8A/8sinA​
alexgriva [62]

I assume you're supposed to establish the identity,

cos(A) cos(2A) cos(4A) = 1/8 sin(8A) / sin(A)

Recall the double angle identity for sine:

sin(2<em>x</em>) = 2 sin(<em>x</em>) cos(<em>x</em>)

Then you have

sin(8A) = 2 sin(4A) cos(4A)

sin(8A) = 4 sin(2A) cos(2A) cos(4A)

sin(8A) = 8 sin(A) cos(A) cos(2A) cos(4A)

==>   sin(8A)/(8 sin(A)) = cos(A) cos(2A) cos(4A)

as required.

3 0
3 years ago
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