Answer:
5.64
Step-by-step explanation:
Answer:
A.Swing two arcs above and below the radius.
Step-by-step explanation:
The statement in option A is not used in constructing an inscribed hexagon. While constructing a inscribed hexagon, swinging of the arcs is done on only one direction to cut the circumference of the circle.
Steps of constructing an inscribed hexagon are :
1. Draw a circle on a paper with the help of a compass.
2. Mark a point on the circumference of the circle and make it a starting point.
3. Now with the same span on the compass, place the compass pointer on the previous point on the circumference and swing a small arc cutting the circumference.
4. Now with same span, place the compass pointer on the intersecting point of the small arc and the circumference and make second small arc on the circumference.
5. Continue making arcs on the circumference until we reach the 1st point.
6. Now join the intersecting points on the circle and make a hexagon.
So it i clear from the above that swinging two arcs below and above the radius is not required. Thus option A is not required.
Answer:
The area of the rectangle is 2820 square inches. The length is 60 inches. The width is 47 inches.
Step-by-step explanation:
Since we know the equation to find the width, we have to set them both to the perimeter of 90 inches. We will use the variable <em>x</em> to represent the length.
<em>x + x - 30 = 90</em>
<em>2x - 30 = 90</em>
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You would then subtract 30 from both sides.
<em>2x = 60</em>
Divide by 2 on both sides, finding that the length (x) is 30 inches.
<em> x = 30 inches.</em>
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Then, subtract 13 inches from the length to find your width.
<em>60 - 13 = 47 inches</em>
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To find your area, you would multiply both of your factors (length and width) together.
<em> 60 x 47 = 2,820</em>
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And those are your answers!
Answer:
17*4 = 68
Step-by-step explanation:
Let width=x m
so length=3x-7
Since area =66m^2
L×B=66
(3x-7)×x=66
3x^2-7x=66
3x^2-7x-66=0
3x^2-(18-11)x-66=0
3x^2-18x+11x-66=0
3x(x-6)+11(x-6)=0
So (x-6)(3x-6)=0
So x=2 and x=6
If x=2
Width=2
Length=2×3-7=-1
So this value of x does not exist because length cannot be negative
So x=6m
Width=6m
length=3×6-7=11m