Answer:
Step-by-step explanation:
(5-1)/(5-1)= 4/4= 1
y - 1 = x - 1
y = x
y - x = 0
the second equation is not
Answer:
- a) 6.5 seconds
- b) 13 seconds
- c) 679 ft
Step-by-step explanation:
<u>Given function:</u>
a) <u>Maximum height is the vertex.</u> The ball reaches the maximum after:
- h = -208/2(-16) = 6.5 seconds
b) <u>Time the ball was in the air:</u>
Solving we get approximately t = 13 seconds
c) <u>Maximum height is at vertex, we found t above:</u>
- h(6.5) = -16(6.5)^2 + 208*6.5 + 3 = 679 ft
We are told in the question that 1 carat is equal to 200 mg.
The Hope Diamond is 44.5 carats. Let's multiply the weight of 1 carat by 44.5 to get the weight of the Hope Diamond in mg:
The total weight of the Hope Diamond is 8,900 mg. However the question asks for the weight in grams. There are 1000 mg in 1 gram, so let's divide the known weight of the Hope Diamond in mg by 1000 to get the weight converted to grams:
Now we know that
the weight of the Hope Diamond is equal to 8.9 grams.
(jk)(x)= j (k(x)) = j(9-2x)
= -7(9-2x) = -63 + 14x
but i see there is no such option. may be second option is typo.
so you can select 2nd option
The parabolic motion is an illustration of a quadratic function
The equation that models that path of the rocket is y = -16/31x^2 + 256/31x - 880/31
<h3>How to model the function?</h3>
Given that:
x stands for time and y stands for height in feet
So, we have the following coordinate points
(x,y) = (5,0), (11,0) and (10,80)
A parabolic motion is represented as:
y =ax^2 + bx + c
At (5,0), we have:
25a + 5b + c = 0
c= -25a - 5b
At (11,0), we have:
121a + 11b + c = 0
Substitute c= -25a - 5b
121a + 11b -25a - 5b = 0
Simpify
96a + 6b = 0
At (10,80), we have:
100a + 10b + c = 80
Substitute c= -25a - 5b
100a + 10b - 25a -5b = 80
75a -5b = 80
Divide through by 5
15a -b = 16
Make b the subject
b = 15a + 16
Substitute b = 15a + 16 in 96a + 6b = 0
96a + 6(15a + 16) = 0
Expand
96a + 90a + 96 = 0
This gives
186a = -96
Solve for a
a = -16/31
Recall that:
b = 15a + 16
So, we have:
b = -15 * 16/31 + 16
b =-240/31 + 16
Take LCM
b =(-240 + 31 * 16)/31
[tex]b =256/31
Also, we have:
c= -25a - 5b
This gives
c= 25*16/31 - 5 * 256/31
Take LCM
c= -880/31
Recall that:
y =ax^2 + bx + c
This gives
y = -16/31x^2 + 256/31x - 880/31
Hence, the equation that models that path of the rocket is y = -16/31x^2 + 256/31x - 880/31
Read more about parabolic motion at:
brainly.com/question/1130127
