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Simora [160]
3 years ago
14

Write the​ point-slope form of the​ line's equation satisfying the given conditions. Then use the​ point-slope form of the equat

ion to write the​ slope-intercept form of the equation. Slopeequals4​, passing through ​(6​,7​)
Mathematics
2 answers:
Advocard [28]3 years ago
8 0

Answer:

y - 7 = 4(x - 6)

y - 7 = 4x - 24

y = 4x - 24 + 7

y = 4x - 17

Fed [463]3 years ago
4 0

Answer:

Step-by-step explanation:

The point slope form is expressed as

y - y1 = m(x - x1)

Where

m represents slope of the line

y1 represents initial value of y

x1 represents initial value of x

The given line has a slope of 4 and passes through (6, 7)

y1 = 7

x1 = 6

Therefore, the equation becomes

y - 7 = 4(x - 6)

The equation of a straight line can be represented in the slope-intercept form, y = mx + c

Where c represents the y intercept.

From the point slope form,

y - 7 = 4x - 24

y = 4x - 24 + 7

y = 4x - 17

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At what point on the curve y = 19 2x is the tangent line perpendicular to the line 20x 4y = 1?
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The points are; (7/2, -1/2).

<h3>What is the given point?</h3>

Now the tangent line is given as;20x 4y = 1. When we rewrite it in the slope intercept form, we have the equation as; y = 1 - 20x/4 or y = 1/4 - 5x.

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Learn more about normal curve:brainly.com/question/10664419

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