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Simora [160]
3 years ago
14

Write the​ point-slope form of the​ line's equation satisfying the given conditions. Then use the​ point-slope form of the equat

ion to write the​ slope-intercept form of the equation. Slopeequals4​, passing through ​(6​,7​)
Mathematics
2 answers:
Advocard [28]3 years ago
8 0

Answer:

y - 7 = 4(x - 6)

y - 7 = 4x - 24

y = 4x - 24 + 7

y = 4x - 17

Fed [463]3 years ago
4 0

Answer:

Step-by-step explanation:

The point slope form is expressed as

y - y1 = m(x - x1)

Where

m represents slope of the line

y1 represents initial value of y

x1 represents initial value of x

The given line has a slope of 4 and passes through (6, 7)

y1 = 7

x1 = 6

Therefore, the equation becomes

y - 7 = 4(x - 6)

The equation of a straight line can be represented in the slope-intercept form, y = mx + c

Where c represents the y intercept.

From the point slope form,

y - 7 = 4x - 24

y = 4x - 24 + 7

y = 4x - 17

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Step-by-step explanation:

The ratio of the larger figure to the smaller figure is simplfying 30/12 to 5/2

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3 years ago
The nurse needs to mix 2% solution with 10% solution to get 10 ml of the prescribed 6% solution. What amount of each solution do
xenn [34]

<em>Volumes of 2% Solution = </em><em>5 ml</em>

<em>Volumes of 10% Solution = </em><em>5 ml</em>

\texttt{ }

<h3>Further explanation</h3>

Simultaneous Linear Equations could be solved by using several methods such as :

  • <em>Elimination Method</em>
  • <em>Substitution Method</em>
  • <em>Graph Method</em>

If we have two linear equations with 2 variables x and y , then we need to find the value of x and y that satisfying the two equations simultaneously.

Let us tackle the problem!

\texttt{ }

<em>Let:</em>

<em>Volumes of 2% Solution = x</em>

<em>Volumes of 10% Solution = y</em>

\texttt{ }

<em>Total Volume = 10 ml</em>

\boxed{x + y = 10} → <em>Equation 1</em>

\texttt{ }

<em>The nurse needs to mix 2% solution with 10% solution to get 10 ml of the prescribed 6% solution</em>.

2 \% x + 10 \% y = 6 \% (10)

2x + 10y = 6(10)

\boxed{x + 5y = 30} → <em>Equation 2</em>

\texttt{ }

<em>Equation 1 - Equation 2:</em>

( x + y ) - ( x + 5y ) = 10 - 30

-4y = -20

y = -20 \div -4

y = 5 \texttt{ ml}

\texttt{ }

x + y = 10

x + 5 = 10

x = 5 \texttt{ ml}

\texttt{ }

<h2>Conclusion:</h2>

<em>Volumes of 2% Solution = </em><em>5 ml</em>

<em>Volumes of 10% Solution = </em><em>5 ml</em>

\texttt{ }

<h3>Learn more</h3>
  • Perimeter of Rectangle : brainly.com/question/12826246
  • Elimination Method : brainly.com/question/11233927
  • Sum of The Ages : brainly.com/question/11240586

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Simultaneous Linear Equations

Keywords: Simultaneous , Elimination , Substitution , Method , Linear , Equations

6 0
2 years ago
Is the student correct?​
Pachacha [2.7K]
Yes the student is correct
6 0
3 years ago
Can anyone help me with Question 7? I’m not good at word problems :(
romanna [79]
You just have to find the angle whose sine is 0.1045. Use the sin-1 key on your calculator  ( make sure its set to degrees first)

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