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Alona [7]
3 years ago
11

Simplify the algebraic expression: x(x + 3) + x(2x - 4) + 6

Mathematics
2 answers:
Paha777 [63]3 years ago
8 0

Answer

3x2-x+6 i hope this helps

marusya05 [52]3 years ago
6 0

Step-by-step explanation:

x(x + 3) + x(2x - 4) + 6

First, let's distribute the x variable to each term in the first parenthesis:

x^{2} + 3x + x(2x - 4) + 6

Next, let's distribute the x variable to each term in the second parenthesis:

x^{2} + 3x + 2x^{2} - 4x + 6

Next, let's group like terms together:

(x^{2} + 2x^{2}) + (3x - 4x) + (6)

Finally, let's add or subtract like terms to get the result:

3x^{2} - x + 6

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Does anyone know this?
barxatty [35]

Answer:

\Huge \boxed{-2}

Step-by-step explanation:

f(x)=-2x^2-2x+10

For f(2), the input of the function is 2.

Let x = 2.

f(2)=-2(2)^2-2(2)+10

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3 years ago
Read 2 more answers
A group of retired admirals, generals, and other senior military leaders, recently published a report, "Too Fat to Fight". The r
weqwewe [10]

Answer:

z=\frac{0.694 -0.75}{\sqrt{\frac{0.75(1-0.75)}{180}}}=-1.735  

p_v =P(z  

If we compare the p value obtained and the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of americans between 17 to 24 that not qualify for the military is significantly less than 0.75 or 75% .  

Step-by-step explanation:

1) Data given and notation  

n=180 represent the random sample taken  

X=125 represent the number of americans between 17 to 24 that not qualify for the military

\hat p=\frac{125}{180}=0.694 estimated proportion of americans between 17 to 24 that not qualify for the military

p_o=0.75 is the value that we want to test  

\alpha=0.05 represent the significance level  

Confidence=95% or 0.95  

z would represent the statistic (variable of interest)  

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that less than 75% of Americans between the ages of 17 to 24 do not qualify for the military :  

Null hypothesis: p\geq 0.75  

Alternative hypothesis:p < 0.75  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.  

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.694 -0.75}{\sqrt{\frac{0.75(1-0.75)}{180}}}=-1.735  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(z  

If we compare the p value obtained and the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of americans between 17 to 24 that not qualify for the military is significantly less than 0.75 or 75% .  

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2 years ago
find the probability of at least 3 successes in a 3 trials of a binomial experiment i which the probability of successe is 50%
katrin2010 [14]

each trial is independent so do

.5 x .5 x .5 or .5^3

.125 is the probability.

7 0
3 years ago
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