Answer:
Five times
Explanation:
Given the codes as follows:
- int upperCaseLetters = 0;
- String str = "abcdEfghI";
- boolean found = false;
-
- for (int i = 0; i < str.length() && !found; i++)
- {
- char ch = str.charAt(i);
-
- if (Character.isUpperCase(ch))
- {
- found = true;
- }
- }
The for loop will stop when the first uppercase letter is found in the str. This condition is set in the for loop condition ( i < str.length() && !found)
Since the the first upper case letter is the fifth character in the given str, the for loop will run for five rounds. In the fifth round the condition in the if statement (Line 9) will be evaluated to true and then set the true value to found variable (Line 11). This will terminate the loop in the next iteration.
Barcode hospital operating suites, cardiac and intensive care units.
Answer:
The answer is "Option A"
Explanation:
Escalation is the process of manipulating a bug, design failure in software program to obtain elevated access to the resources, which are usually shielded from the user, and wrong choices can be described as follows:
- In option B, It is wrong because It can't provide any type of problem-solving.
- In option C, It is wrong because it is a searching module.
- In option D, It is wrong because it is used to verify the system.
