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dolphi86 [110]
3 years ago
10

4 + 2/7x = 8 what does x equal

Mathematics
2 answers:
frozen [14]3 years ago
8 0
Subtract 4 from both sides of the equation
you will end up with 2/7x=4
next multiply 7x by both sides
you will end up with 2=28x
next divide 28 from both sides
you will end up with x=1/14 in
fraction form. Hope this helps.
Eduardwww [97]3 years ago
5 0
4+2/7x=8
minus 4 from both sides
2/7x=4

now there are 2 paths possible
1. 2/(7x)=4, if so, go to AAAAAA
2. (2/7)x=4, if so, go to BBBBBB


AAAA
2/(7x)=4
times both sides by 7x
2=28x
divide both sides by 28
1/14=x

BBBBBBB
(2/7)x=4
times both sides by 7/2
x=28/2
x=14


x=1/14 or 14 depending on how the fraction is
1/14 if 2/(7x), 14 if (2/7)x
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Consider the volume of the region shown below, which shows a right circular cone with top radius 3 cm and height 10 cm. We have
koban [17]
I have the same problem here with a slight change in the given values:

radius is 2 & height of 6 indicates the bounding line is y = 3 x---> x = y / 3.... 

<span>thus the [ π radius ² thickness ] yields π (y² / 9 ) <span>dy ,</span> y in [ 0 , 6 ] for the volume... </span>

a Riemann sum is then : y_i = 0 + i [ 6 / n ] = 6 i / n , i = 1,2,3...n and do a right side sum 

<span>π Σ { i = 1,2,3..n } [ 36 i² / 9 n² ] [ 6 / n ]
</span>
I hope my guide has come to your help. God bless and have a nice day ahead!
5 0
3 years ago
A jar has 570 marbles of different colors.The ratio of red to blue marbles are 2:3 and red to green is 4:5.how many marbles of e
iVinArrow [24]

Answer:

The number of red marbles = 152

The number of blue marbles = 228 and

the number of green marbles = 190

Step-by-step explanation:

Let x be the number of red marbles, y be the number of blue marbles and z be the number of green marbles.

It is given that the total marbles = 570.

Therefore, x + y + z = 570 --- (1)

It is also given that the ratio of red to blue marbles is 2 : 3.

Therefore, x : y = 2 : 3

or 3x = 2y --- (2)

It is also given that the ratio of red to green marbles is 4 : 5.

Therefore, x : z = 4 : 5

or 5x = 4z --- (3)

From (2), y=\frac{3x}{2}

From (3), z=\frac{5x}{4}

Substituting the above in (1), we get,

x+\frac{3x}{2} +\frac{5x}{4} =570

Multiply both sides by 4.

4x + 6x + 5x = 2280

15x = 2280

Divide both sides by 15.

x = 152

Hence,

y = \frac{3(152)}{2}

y = 228

z = \frac{5(152)}{4}

z = 190

Therefore,

The number of red marbles = 152

The number of blue marbles = 228 and

the number of green marbles = 190

<u>Check:</u>

Total number of marbles = 152 + 228 + 190 = 570

Ratio of red to blue marbles = 152 : 228 = 2 : 3

Ratio of red t green marbles = 152 : 190 = 4 : 5


8 0
3 years ago
What is 42789 x 54678
vichka [17]
42789 times 54678
is 2,339,616,942

Show Work:
<span>Calculate 9 x 8, which is 72.
Since 72 is two-digit, we carry the first digit 7 to the next column.
</span>
3 <span>Calculate 8 x 8, which is 64. Now add the carry digit of 7, which is 71.
Since 71 is two-digit, we carry the first digit 7 to the next column.
</span>
4 <span>Calculate 7 x 8, which is 56. Now add the carry digit of 7, which is 63.
Since 63 is two-digit, we carry the first digit 6 to the next column.
</span>

5 <span>Calculate 2 x 8, which is 16. Now add the carry digit of 6, which is 22.
Since 22 is two-digit, we carry the first digit 2 to the next column.
</span>
6 <span>Calculate 4 x 8, which is 32. Now add the carry digit of 2, which is 34.
Since 34 is two-digit, we carry the first digit 3 to the next column.
</span>
7 <span>Bring down the carry digit of 3.
</span>
8 <span>Calculate 9 x 7, which is 63.
Since 63 is two-digit, we carry the first digit 6 to the next column.
</span>
9 <span>Calculate 8 x 7, which is 56. Now add the carry digit of 6, which is 62.
Since 62 is two-digit, we carry the first digit 6 to the next column.
</span>
10 <span>Calculate 7 x 7, which is 49. Now add the carry digit of 6, which is 55.
Since 55 is two-digit, we carry the first digit 5 to the next column.
</span>
11 <span>Calculate 2 x 7, which is 14. Now add the carry digit of 5, which is 19.
Since 19 is two-digit, we carry the first digit 1 to the next column.
</span>
12 <span>Calculate 4 x 7, which is 28. Now add the carry digit of 1, which is 29.
Since 29 is two-digit, we carry the first digit 2 to the next column.
</span>

13 <span>Bring down the carry digit of 2.
</span>
14 <span>Calculate 9 x 6, which is 54.
Since 54 is two-digit, we carry the first digit 5 to the next column.
</span>
15 <span>Calculate 8 x 6, which is 48. Now add the carry digit of 5, which is 53.
Since 53 is two-digit, we carry the first digit 5 to the next column.
</span>

16 <span>Calculate 7 x 6, which is 42. Now add the carry digit of 5, which is 47.
Since 47 is two-digit, we carry the first digit 4 to the next column.
</span>

17 <span>Calculate 2 x 6, which is 12. Now add the carry digit of 4, which is 16.
Since 16 is two-digit, we carry the first digit 1 to the next column.
</span>

18 <span>Calculate 4 x 6, which is 24. Now add the carry digit of 1, which is 25.
Since 25 is two-digit, we carry the first digit 2 to the next column.
</span>

19 <span>Bring down the carry digit of 2.
</span>

20 <span>Calculate 9 x 4, which is 36.
Since 36 is two-digit, we carry the first digit 3 to the next column.
</span>
21 <span>Calculate 8 x 4, which is 32. Now add the carry digit of 3, which is 35.
Since 35 is two-digit, we carry the first digit 3 to the next column.
</span>
22 <span>Calculate 7 x 4, which is 28. Now add the carry digit of 3, which is 31.
Since 31 is two-digit, we carry the first digit 3 to the next column.
</span>
23 <span>Calculate 2 x 4, which is 8. Now add the carry digit of 3, which is 11.
Since 11 is two-digit, we carry the first digit 1 to the next column.
</span>
24 <span>Calculate 4 x 4, which is 16. Now add the carry digit of 1, which is 17.
Since 17 is two-digit, we carry the first digit 1 to the next column.
</span>
25 <span>Bring down the carry digit of 1.
</span>
26 <span>Calculate 9 x 5, which is 45.
Since 45 is two-digit, we carry the first digit 4 to the next column.
</span>
27 <span>Calculate 8 x 5, which is 40. Now add the carry digit of 4, which is 44.
Since 44 is two-digit, we carry the first digit 4 to the next column.
</span>
28 <span>Calculate 7 x 5, which is 35. Now add the carry digit of 4, which is 39.
Since 39 is two-digit, we carry the first digit 3 to the next column.
</span>
29 <span>Calculate 2 x 5, which is 10. Now add the carry digit of 3, which is 13.
Since 13 is two-digit, we carry the first digit 1 to the next column.
</span>
30 <span>Calculate 4 x 5, which is 20. Now add the carry digit of 1, which is 21.
Since 21 is two-digit, we carry the first digit 2 to the next column.
</span>
31 <span>Bring down the carry digit of 2.
</span>
32 <span>Calculate 342312 + 2995230 + 25673400 + 171156000 + 2139450000, which is 2339616942</span>
<span>         </span>
6 0
3 years ago
Read 2 more answers
Given the figure below, find the values of x and z.<br> (10x - 65)<br> (9x - 49)
nexus9112 [7]
(10x - 65) degrees is equal to (9x - 49) degrees, therefore you can set them into an equation.

(10x - 65) = (9x - 49)

By subtracting 9x in both sides,

(10x - 9x) - 65 = (9x -9x) - 49

x - 65 = -49

By adding 65 in both sides,


x - 65 + 65= -49 + 65
x = 16


Next, to find the value of z, it’s important to know that the straight line has 180 degrees. Then you would substitute the x value you found into one of your equation and subtract it from 180.

10 (16) - 65 = 160 - 65 = 95

Now you know that (10x - 65) degrees is equal to 95 degrees,

180 - 95 = z = 85


Answer: x = 16
z = 85
5 0
2 years ago
The coordinates G(7,3), H(9, 0), (5, -1) form what type of polygon?
Marrrta [24]

Answer:

Is an acute triangle

Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

G(7,3), H(9, 0), I(5, -1)

step 1

Find the distance GH

substitute in the formula

d=\sqrt{(0-3)^{2}+(9-7)^{2}}

d=\sqrt{(-3)^{2}+(2)^{2}}

GH=\sqrt{13}\ units

step 2

Find the distance IH

substitute in the formula

d=\sqrt{(0+1)^{2}+(9-5)^{2}}

d=\sqrt{(1)^{2}+(4)^{2}}

IH=\sqrt{17}\ units

step 3

Find the distance GI

substitute in the formula

d=\sqrt{(-1-3)^{2}+(5-7)^{2}}

d=\sqrt{(-4)^{2}+(-2)^{2}}

GI=\sqrt{20}\ units

step 4

Verify what type of triangle is the polygon

we know that

If applying the Pythagoras Theorem

c^{2}=a^{2}+b^{2} ----> is a right triangle

c^{2}> a^{2}+b^{2} ----> is an obtuse triangle

c^{2}< a^{2}+b^{2} ----> is an acute triangle

where

c is the greater side

we have

c=\sqrt{20}\ units

a=\sqrt{17}\ units

b=\sqrt{13}\ units

substitute

c^{2}= (\sqrt{20})^{2}=20

a^{2}+b^{2}=(\sqrt{17})^{2}+(\sqrt{13})^{2}=30

therefore

c^{2}< a^{2}+b^{2}

Is an acute triangle

6 0
3 years ago
Read 2 more answers
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