What is the distance between -45 and -98 on a number line?

Create a word problem that involves speed

lana66690 [7]

A hockey puck is sliding on frictionless ice on an infinite hockey rink.
Its speed is 36 km/hour. How far does the puck slide in 10 seconds ?

(36 km/hr) x (1,000 m/km) x (1 hr/3600 sec) x (10sec) =

(36 x 1,000 x 10 / 3,600) meters = 100 meters

What is the puck's speed in miles per hour ?

(36 km/hr) x (0.6214 mi/km) = 22.37 mi/hr

6 0

4 years ago

What is 1/3 to the power of 2

slamgirl [31]

Answer:

Brainliest!

Step-by-step explanation:

1/3 is going to be like

1^2

------

3^2

= 1/9

7 0

3 years ago

4z^3-3z^5+2z^4+z+1 please solve this question please!

lbvjy [14]

SOLUTION

TO DETERMINE

The degree of the polynomial

CONCEPT TO BE IMPLEMENTED

POLYNOMIAL

Polynomial is a mathematical expression consisting of variables, constants that can be combined using mathematical operations addition, subtraction, multiplication and whole number exponentiation of variables

DEGREE OF A POLYNOMIAL

Degree of a polynomial is defined as the highest power of its variable that appears with nonzero coefficient

When a polynomial has more than one variable, we need to find the degree by adding the exponents of each variable in each term.

EVALUATION

Here the given polynomial is

In the above polynomial variable is z

The highest power of its variable ( z ) that appears with nonzero coefficient is 5

Hence the degree of the polynomial is 5

FINAL ANSWER

The degree of the polynomial is 5

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

1. Find the degree of 2020?

brainly.in/question/25939171

2. Write the degree of the given polynomial: 5x³+4x²+7x

4 0

3 years ago

Assume that 24.5% of people have sleepwalked. Assume that in a random sample of 1478 adults, 369 have sleepwalked. a. Assuming t

solniwko [45]

Answer:

a) 0.3483 = 34.83% probability that 369 or more of the 1478 adults have sleepwalked.

b) 369 < 403.4, which means that 369 is less than 2.5 standard deviations above the mean, and thus, a result of 369 is not significantly high.

c) Since the sample result is not significant, it suggests that the rate of 24.5% is a good estimate for the percentage of people that have sleepwalked.

Step-by-step explanation:

We use the normal approximation to the binomial to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

A result is considered significantly high if it is more than 2.5 standard deviations above the mean.

Normal probability distribution

Problems of normally distributed distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .

Assume that 24.5% of people have sleepwalked.

This means that $p = 0.245$

Sample of 1478 adults:

This means that $n = 1478$

Mean and standard deviation:

$\mu = 1478*0.245 = 362.11$

$\sigma = \sqrt{1478*0.245*0.755} = 16.5346$

a. Assuming that the rate of 24.5% is correct, find the probability that 369 or more of the 1478 adults have sleepwalked.

Using continuity correction, this is $P(X \geq 369 - 0.5) = P(X \geq 368.5)$ , which is 1 subtracted by the p-value of Z when X = 368.5.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{368.5 - 362.11}{16.5346}$

$Z = 0.39$

$Z = 0.39$ has a p-value of 0.6517

1 - 0.6517 = 0.3483

0.3483 = 34.83% probability that 369 or more of the 1478 adults have sleepwalked.

b. Is that result of 369 or more significantly high?

362.11 + 2.5*16.5346 = 403.4

369 < 403.4, which means that 369 is less than 2.5 standard deviations above the mean, and thus, a result of 369 is not significantly high.

c. What does the result suggest about the rate of 24.5%?

Since the sample result is not significant, it suggests that the rate of 24.5% is a good estimate for the percentage of people that have sleepwalked.

3 0

3 years ago

Ms.Groves has trays of paint for students in her art class.each tray has 5 colors.one of the colors is purple.what fraction of t

seropon [69]

So we need to find the fraction of many times does purple show up in 20 trays in which every tray has 5 colors. To find the answer we need to find the overall number of all colors and that is 20 trays * 5 colors and that equals to 100 colors. So purple shows 20 times and 20/100 is 1/5 when we simplify the fraction.

4 0

3 years ago

Read 2 more answers