Convert 1.5 and 0.8 from meters to millimeters,
1500*800,
A=120,000
<span>2/5g+3h-6 when g=10 and h=6
</span><span>2/5 (10) +3(6) - 6
</span><span>= 4 + 18 - 6
= 16
</span>
Answer:
<u>The chemistry class mixed 120 gallons of 12% isopropyl alcohol and 180 gallons of 42% isopropyl alcohol.</u>
Step-by-step explanation:
1. Let's review the information given to us to answer the question correctly:
Amount of isopropyl alcohol made by the chemistry class = 300 of 30%
Amount of 12% isopropyl alcohol mixed by the chemistry class = x
Amount of 42% isopropyl alcohol mixed by the chemistry class = 300 - x
2. How much of each did they use?
Let's write our equation to solve for x, this way:
30% = 0.3, 12% = 0.12, 42% = 0.42
0.12x + 0.42 (300 - x) = 0.3 * 300
0.12x + 126 - 0.42x = 90
-0.3x = 90 - 126
-0.3x = -36
x = -36/-0.3
<u>x = 120 ⇒ 300 - x = 180</u>
<u>Let's prove x = 120 is correct</u>
0.12x + 0.42 (300 - x) = 0.3 * 300
0.12 * 120 + 0.42 (300 - 120) = 0.3 * 300
14.4 + 75.6 = 90
90 = 90
<u>We proved x = 120 is correct</u>
Answer:
(arranged from top to bottom)
System #3, where x=6
System #1, where x=4
System #7, where x=3
System #5, where x=2
System #2, where x=1
Step-by-step explanation:
System #1: x=4

To solve, start by isolating your first equation for y.

Now, plug this value of y into your second equation.

System #2: x=1

Isolate your second equation for y.

Plug this value of y into your first equation.

System #3: x=6

Isolate your first equation for y.

Plug this value of y into your second equation.

System #4: all real numbers (not included in your diagram)

Plug your value of y into your second equation.

<em>all real numbers are solutions</em>
System #5: x=2

Isolate your second equation for y.

Plug in your value of y to your first equation.

System #6: no solution (not included in your diagram)

Isolate your first equation for y.

Plug your value of y into your second equation.

<em>no solution</em>
System #7: x=3

Plug your value of y into your second equation.
