Evaluate the expression.<br> 52 – 4.6 +11<br> Enter your answer in the box.

Can you please help me understand how to solve this

nasty-shy [4]

Answer:

Hope you understand this

Step-by-step explanation:

HAVE A GOOD DAY!

8 0

2 years ago

Read 2 more answers

12. Without using any calculator, work out the

masya89 [10]

3/25677777777ssdtyyyy

6 0

2 years ago

Can you help me!!!!!!!!!!!!!!!!!!!!!!!!!

Alexxandr [17]

Answer:

B. Lease

Step-by-step explanation:

Cash has value

A vehicle has value

A house has value

But a lease itself does not have value

Asset is something you own that has value

Hope this helped!

Have a supercalifragilisticexpialidocious day!

5 0

2 years ago

g 1) The rate of growth of a certain type of plant is described by a logistic differential equation. Botanists have estimated th

alexira [117]

Answer:

a) The expression for the height, 'H', of the plant after 't' day is;

$H = \dfrac{30}{1 + 5\cdot e^{-(2.02732554 \times 10^{-3}) \cdot t}}$

b) The height of the plant after 30 days is approximately 19.426 inches

Step-by-step explanation:

The given maximum theoretical height of the plant = 30 in.

The height of the plant at the beginning of the experiment = 5 in.

a) The logistic differential equation can be written as follows;

$\dfrac{dH}{dt} = K \cdot H \cdot \left( M - {P} \right)$

Using the solution for the logistic differential equation, we get;

$H = \dfrac{M}{1 + A\cdot e^{-(M\cdot k) \cdot t}}$

Where;

A = The condition of height at the beginning of the experiment

M = The maximum height = 30 in.

Therefore, we get;

$5 = \dfrac{30}{1 + A\cdot e^{-(30\cdot k) \cdot 0}}$

$1 + A = \dfrac{30}{5} = 6$

A = 5

When t = 20, H = 12

We get;

$12 = \dfrac{30}{1 + 5\cdot e^{-(30\cdot k) \cdot 20}}$

$1 + 5\cdot e^{-(30\cdot k) \cdot 20} = \dfrac{30}{12} = 2.5$

$5\cdot e^{-(30\cdot k) \cdot 20} = 2.5 - 1 = 1.5$

∴ -(30·k)·20 = ㏑(1.5)

k = ㏑(1.5)/(30 × 20) ≈ 6·7577518 × 10⁻⁴

k ≈ 6·7577518 × 10⁻⁴

Therefore, the expression for the height, 'H', of the plant after 't' day is given as follows

$H = \dfrac{30}{1 + 5\cdot e^{-(30\times 6.7577518 \times 10^{-4}) \cdot t}} = \dfrac{30}{1 + 5\cdot e^{-(2.02732554 \times 10^{-3}) \cdot t}}$

b) The height of the plant after 30 days is given as follows

$H = \dfrac{30}{1 + 5\cdot e^{-(2.02732554 \times 10^{-3}) \cdot t}}$

At t = 30, we have;

$H = \dfrac{30}{1 + 5\cdot e^{-(2.02732554 \times 10^{-3}) \times 30}} \approx 19.4258866473$

The height of the plant after 30 days, H ≈ 19.426 in.

3 0

3 years ago

Find the other endpoint given the following <br> Endpoint: (5,-3) Midpoint: (7,-6)

Phantasy [73]

The answer is (9, -9) for The second midpoint.

Let's start by calling the known endpoint L and the unknown K. We'll call the midpoint M. In order to find this, we must first note that to find a midpoint we need to take the average of the endpoints. To do this we add them together and then divide by 2. So, using that, we can write a formula and solve for each part of the k coordinates. We'll start with just x values.

(Kx + Lx)/2 = Mx

(Kx + 5)/2 = 7

Kx + 5 = 14

Kx = 9

And now we do the same thing for y values

(Ky + Ly)/2 = My

(Ky + -3)/2 = -6

Ky + -3 = -12

Ky = -9

This gives us the final point of (9, -9)

6 0

3 years ago

Evaluate the expression. 52 – 4.6 +11 Enter your answer in the box.