Answer:
1. d 2. d 3. a
Step-by-step explanation:
1. factor
((w-4)(w-6))/((w-5)(w-6))+8/(w-5)
solve
(w-4)/(w-5)+8/(w-5)
(w+4)/(w-5), so d
2.factor
((b+2)(b-4))((b+2)(b-1))-6/(b-1)
solve
(b-4)/(b-1)-6(b-1)
(b-10)/(b-1), so d
3. (2/5t-3/3t)/(1/2t+1/2t)
(2/5t-1/t)/(2/2t)
(2/5t-1/t)/(1/t)
t(2/5t-1/t)
2/5-1=-3/5, so a
Answer:
x = 2
Step-by-step explanation:
2(2x+1-x)=6
2(x+1)=6 add common factors
2x+2=6 distribute the 2
2x=4 subrtract 2 on both sides
x=2 divide 2 on both sides
49: 1 7, 49
84: 1, 2, 3, 4, 6, 7, 12, 14, 21, 28, 42, 84
The GCF is 7
Answer:
50 a^2 b c^2
Step-by-step explanation:
I'm quite confused about your question, but I try my best. I have attached the explanation above. Hopefully this will help
All it takes for a relation to be a function is for each possible first number of a pair there's only one possible second number.
So if any of the sets has two pairs with the same first number, that one's not a function.
The last one has (3,2) and (3,5) so isn't a function.
