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3 years ago

A rectangle’s perimeter and its area have the same numerical value. The width of the

Mathematics

1 answer:

Zolol [24]3 years ago

7 0

Step-by-step explanation:

6 units.

(3*2)+2x=3x

Set the perimeter equal to the area

x(length)=6 units

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if jules asked 100 people how many years of school dud they have and what's their annual income what's the association on a scat

AleksAgata [21]

It would be a positive correlation because they had to do 1 or more years and they can't do negative years.

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2 years ago

The graph shows the solution to which system of equations?

borishaifa [10]

Ur solution is gonna be the point where ur lines intersect....and that is (1,-1)

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3 years ago

In the figure below, MN | KL and are intersected by transversals ML and KN M 1551 What is the measure of , XMN?

Schach [20]

Answer:

∠ XMN = 50°

Step-by-step explanation:

∠ XNM and ∠ XKL are alternate angles and are congruent, then

∠ XNM = 35°

The sum of the 3 angles in a triangle = 180° , so

∠ XMN = 180° - (95 + 35)° = 180° - 130° = 50°

5 0

2 years ago

Find the value of each variable.<br>

V125BC [204]

Answer:

see explanation

Step-by-step explanation:

Using the exact values of the trigonometric ratios

sin60° = $\frac{\sqrt{3} }{2}$ , cos60° = $\frac{1}{2}$

sin45° = cos45° = $\frac{1}{\sqrt{2} }$

Using the sine ratio on the right triangle on the left

sin60° = $\frac{opposite}{hypotenuse}$ = $\frac{a}{4\sqrt{3} }$ = $\frac{\sqrt{3} }{2}$

Cross- multiply

2a = 4 $\sqrt{3}$ × $\sqrt{3}$ = 12 ( divide both sides by 2 )

a = 6

Using the cosine ratio on the same right triangle

cos60° = $\frac{adjacent}{hypotenuse}$ = $\frac{c}{4\sqrt{3} }$ = $\frac{1}{2}$

Cross- multiply

2c = 4 $\sqrt{3}$ ( divide both sides by 2 )

c = 2 $\sqrt{3}$

------------------------------------------------------------------------------------------

Using the sine/cosine ratios on the right triangle on the right

sin45° = $\frac{a}{b}$ = $\frac{6}{b}$ = $\frac{1}{\sqrt{2} }$

Cross- multiply

b = 6 $\sqrt{2}$

cos45° = $\frac{d}{b}$ = $\frac{d}{6\sqrt{2} }$ = $\frac{1}{\sqrt{2} }$

Cross- multiply

$\sqrt{2}$ d = 6 $\sqrt{2}$ ( divide both sides by $\sqrt{2}$ )

d = 6

------------------------------------------------------------------------------------------------

a = 6, b = 6 $\sqrt{2}$ , c = 2 $\sqrt{3}$ , d = 6

3 0

3 years ago

Which diagram shows the percent equivalent to 3/5

Minchanka [31]

Answer:

the last one

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers