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____ [38]
3 years ago
5

A rectangle’s perimeter and its area have the same numerical value. The width of the

Mathematics
1 answer:
Zolol [24]3 years ago
7 0

Step-by-step explanation:

6 units.

(3*2)+2x=3x

Set the perimeter equal to the area

x(length)=6 units

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if jules asked 100 people how many years of school dud they have and what's their annual income what's the association on a scat
AleksAgata [21]

It would be a positive correlation because they had to do 1 or more years and they can't do negative years.

5 0
2 years ago
The graph shows the solution to which system of equations?
borishaifa [10]
Ur solution is gonna be the point where ur lines intersect....and that is (1,-1)

so its just a matter of subbing that into ur answer choices to see which one is true.

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5 0
3 years ago
In the figure below, MN | KL and are intersected by transversals ML and KN M 1551 What is the measure of , XMN?
Schach [20]

Answer:

∠ XMN = 50°

Step-by-step explanation:

∠ XNM and ∠ XKL are alternate angles and are congruent, then

∠ XNM = 35°

The sum of the 3 angles in a triangle = 180° , so

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5 0
2 years ago
Find the value of each variable.<br>​
V125BC [204]

Answer:

see explanation

Step-by-step explanation:

Using the exact values of the trigonometric ratios

sin60° = \frac{\sqrt{3} }{2}, cos60° = \frac{1}{2}

sin45° = cos45° = \frac{1}{\sqrt{2} }

Using the sine ratio on the right triangle on the left

sin60° = \frac{opposite}{hypotenuse} = \frac{a}{4\sqrt{3} } = \frac{\sqrt{3} }{2}

Cross- multiply

2a = 4\sqrt{3} × \sqrt{3} = 12 ( divide both sides by 2 )

a = 6

Using the cosine ratio on the same right triangle

cos60° = \frac{adjacent}{hypotenuse} = \frac{c}{4\sqrt{3} } = \frac{1}{2}

Cross- multiply

2c = 4\sqrt{3} ( divide both sides by 2 )

c = 2\sqrt{3}

------------------------------------------------------------------------------------------

Using the sine/cosine ratios on the right triangle on the right

sin45° = \frac{a}{b} = \frac{6}{b} = \frac{1}{\sqrt{2} }

Cross- multiply

b = 6\sqrt{2}

cos45° = \frac{d}{b} = \frac{d}{6\sqrt{2} } = \frac{1}{\sqrt{2} }

Cross- multiply

\sqrt{2} d = 6\sqrt{2} ( divide both sides by \sqrt{2} )

d = 6

------------------------------------------------------------------------------------------------

a = 6, b = 6\sqrt{2}, c = 2\sqrt{3}, d = 6

3 0
3 years ago
Which diagram shows the percent equivalent to 3/5
Minchanka [31]

Answer:

the last one

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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