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anastassius [24]
3 years ago
9

How far can jovan run in a full hour

Mathematics
1 answer:
yKpoI14uk [10]3 years ago
4 0
2/3(4/3)= 8/9

Jovan ran 8/9 of a mile in a full hour.

Hope this helps!
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Solve each inequality. Graph the solution. *you must draw your graph on your work p-
V125BC [204]
54/2 or 27 should be the answer
3 0
3 years ago
determine the value of x for which r parallels s. then find the measure of angle 1 and the measure of angle 2measure angle 1= 50
Maslowich

According to the picture, angles 1 and 2 have the same measure because they are corresponding angles. Make equal both expressions for 1 and 2 and find x.

\begin{gathered} 50-2x=110-42x \\ 42x-2x=110-50 \\ 40x=60 \\ x=\frac{60}{40} \\ x=\frac{3}{2} \end{gathered}

x is 3/2. Replace this value in both expression to find the measure of each angle.

\begin{gathered} \measuredangle1=50-2x \\ \measuredangle1=50-2(\frac{3}{2}) \\ \measuredangle1=50-3 \\ \measuredangle1=47 \\ \measuredangle2=110-42x \\ \measuredangle2=110-42(\frac{3}{2}) \\ \measuredangle2=110-63 \\ \measuredangle2=47 \end{gathered}

The measure of these angles is 47°

7 0
1 year ago
A northbound bus returns to the bus stop every 20 minutes. The southbound bus returns to the bus stop every 25 minutes.How long
Klio2033 [76]
They  stop at the  same time after 4  times for  the southbound bus to return and five times for the northbound bus returns to the bus stop
 
8 0
3 years ago
Read 2 more answers
There are 33 questions on Allison's
Brums [2.3K]

Answer:

x=15

y=18

Step-by-step explanation:

then x+y=33

and 2x+5y=120

then x=33–y

since 2x+5y=120

then 2(33–y)+5y=120

then 66–2y+5y=120

then 66+3y=120

then 3y=120–66

then 3y=54

then y=54/3

then y=18

then x=33–18=15

4 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cboxed%7B%5Cboxed%7B%20%5Cbegin%7Barray%7D%7B%7D%5Clarge%5Ctt%20The%20%20%5C%5C%20%20%5Ct
larisa86 [58]

Distance formula

\boxed{\sf \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}

Now

#1

\\ \tt\Rrightarrow AB=\sqrt{(3-3)^2+(-2-8)^2}=\sqrt{100}=10units

#2

\\ \tt\Rrightarrow OK=\sqrt{(5-7)^2+(-2+2)^2}=\sqrt{4}=2units

#3

\\ \tt\Rrightarrow LM=\sqrt{(-4-4)^2+(6+4)^2}=\sqrt{64+100}=\sqrt{164}\approx 13units

#4

\\ \tt\Rrightarrow PC=\sqrt{(5-2)^2+(1-3)^2}=\sqrt{9+4}=\sqrt{13}=3.2units

#5

\\ \tt\Rrightarrow QR=\sqrt{(-2+10)^2+(3-9)^2}=\sqrt{64+36}=\sqrt{100}=10units

8 0
3 years ago
Read 2 more answers
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