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Lana71 [14]
2 years ago
10

Plsssssssssssssssssssssssss

Mathematics
1 answer:
SIZIF [17.4K]2 years ago
5 0

Answer:

radius of A= 4.5cm

circumference of A=28.27cm

diameter of B=10cm

circumference of B=31.42cm

Step-by-step explanation:

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in a bag of keys there are 15 silver keys six black keys 11 copper keys and two painted keys of various colors. one key is drawn
Setler79 [48]

Answer:

The best thing to do here is to put each of these into fractions, with the total (31) as the denominator.

14/31= silver

6/31= black

8/31= copper

3/31= various colours.

As you're looking for the keys that are silver or copper, you've got to add the two denominators together, which gives you 14+8= 22.

This cannot be simplified further, therefore, the probability of choosing either a silver or copper key is 22/31.

Hope this answer helps you :)

Have a great day

Mark brainliest

7 0
3 years ago
There were 29 students available for the woodwind section of the school orchestra. 11 students could play the flute, 15 could pl
Dafna11 [192]

Answer:

a. The number of students who can play all three instruments = 2 students

b. The number of students who can play only the saxophone is 0

c. The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only one of the clarinet, saxophone, or flute = 4

Step-by-step explanation:

The total number of students available = 29

The number of students that can play flute = 11 students

The number of students that can play clarinet = 15 students

The number of students that can play saxophone = 12 students

The number of students that can play flute and saxophone = 4 students

The number of students that can play flute and clarinet = 4 students

The number of students that can play clarinet and saxophone = 6 students

Let the number of students who could play flute = n(F) = 11

The number of students who could play clarinet = n(C) = 15

The number of students who could play saxophone = n(S) = 12

We have;

a. Total = n(F) + n(C) + n(S) - n(F∩C) - n(F∩S) - n(C∩S) + n(F∩C∩S) + n(non)

Therefore, we have;

29 = 11 + 15 + 12 - 4 - 4 - 6 + n(F∩C∩S) + 3

29 = 24 + n(F∩C∩S) + 3

n(F∩C∩S) = 29 - (24 + 3) = 2

The number of students who can play all = 2

b. The number of students who can play only the saxophone = n(S) - n(F∩S) - n(C∩S) - n(F∩C∩S)

The number of students who can play only the saxophone = 12 - 4 - 6 - 2 = 0

The number of students who can play only the saxophone = 0

c. The number of students who can play the saxophone and the clarinet but not the flute = n(C∩S) - n(F∩C∩S) = 6 - 2 = 4

The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only the saxophone = 0

The number of students who can play only the clarinet = n(C) - n(F∩C) - n(C∩S) - n(F∩C∩S) = 15 - 4 - 6 - 2 = 3

The number of students who can play only the clarinet = 3

The number of students who can play only the flute = n(F) - n(F∩C) - n(F∩S) - n(F∩C∩S) = 11 - 4 - 4 - 2 = 1

The number of students who can play only the flute = 1

Therefore, the number of students who can play only one of the clarinet, saxophone, or flute = 1 + 3 + 0 = 4

The number of students who can play only one of the clarinet, saxophone, or flute = 4.

6 0
4 years ago
I NEED HELP-AGAIN PLEASE ASAAAPPPP<br> Ok its the question that i attached guys please asap...
LenKa [72]

Answer:

since you have a google browser type the following equation into the bar without searching for it.

Step-by-step explanation:

the instructions or search online.  

8 0
3 years ago
What is a pair of fractions as a pair of fractions with a common denominator of 1/3 and 3/4
scoundrel [369]
4/12 for 1/3 and 9/12 for 3/4
4 0
3 years ago
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I need some help with this question on my homework i would appreciate it if your could help me, the question is...
slavikrds [6]
Oh ok. So I think that x is 83. Because I did this 630-100-121-106-112-108=83. And then I did 630/6 and got 105 and thats the mean.
5 0
3 years ago
Read 2 more answers
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