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2 years ago

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An insurance agent earns a base salary of $28,000, a commission of 2% of sales, and receives an additional fee of $9.00 for each

sale of an investment policy. The agent had total sales of $75,000 and 6 investment policies this month. Find the commission and fees earned.

2 answers:

oksano4ka [1.4K]2 years ago

7 0

Yup it’s 798 plz mark brainliest I need it just got the app

BaLLatris [955]2 years ago

4 0

I agree it is 798!!

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The radar beam sent out by an aeroplane reaches a distance of 120 kilometres and covers an angle of 150 degrees calculate the ar

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1 year ago

Draw and label the final image of △ABC after the given sequence of transformations. Reflect △ABC over the y−axis and then transl

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Answer: The correct option is A.

Explanation:

From the given figure it is noticed that each box in the graph represents the length of 2 units. The coordinates of point A,B and C are (-1,1),(-3,3) and (-2,4) respectively.

If a point reflects over the y-axis then,

$(x,y)\rightarrow(-x,y)$

So after reflecting coordinates of point C become,

$(-2,4)\rightarrow(2,4)$

If a point translated by (a,b), then

$(x,y)\rightarrow(x+a,y+b)$

So, after reflection over y-axis followed by translation by (2,-2), the coordinate of C are,

$(2,4)\rightarrow(2+2,4-2)\\(2,4)\rightarrow(4,2)$

Similarly the image of point A and B are (3,-1) and (5,1) respectively.

The image of C after reflection over y-axis followed by translation by (2,-2) is (4,2), which is shown in only graph A, Therefore A is the correct option.

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2 years ago

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2 years ago

Identify the functions that are continuous on the set of real numbers and arrange them in ascending order of their limits as x t

Studentka2010 [4]

Answer:

g(x)<j(x)<k(x)<f(x)<m(x)<h(x)

Step-by-step explanation:

1. $f(x)=\frac{x^2+x-20}{x^2+4}$

The denominator of f is defined for all real values of x

Therefore, the function is continuous on the set of real numbers

$\lim_{x\rightarrow 5}\frac{x^2+x-20}{x^2+4}=\frac{25+5-20}{25+4}=\frac{10}{29}=0.345$

3. $h(x)=\frac{3x-5}{x^2-5x+7}$

$x^2-5x+7=0$

It cannot be factorize .

Therefore, it has no real values for which it is not defined .

Hence, function h is defined for all real values.

$\lim_{x\rightarrow 5}\frac{3x-5}{x^2-5x+7}=\frac{15-5}{25-25+7}=\frac{10}{7}=1.43$

2. $g(x)=\frac{x-17}{x^2+75}$

The denominator of g is defined for all real values of x.

Therefore, the function g is continuous on the set of real numbers

$\lim_{x\rightarrow 5}\frac{x-17}{x^2+75}=\frac{5-17}{25+75}=\frac{-12}{100}=-0.12$

4. $i(x)=\frac{x^2-9}{x-9}$

x-9=0

x=9

The function i is not defined for x=9

Therefore, the function i is not continuous on the set of real numbers.

5. $j(x)=\frac{4x^2-7x-65}{x^2+10}$

The denominator of j is defined for all real values of x.

Therefore, the function j is continuous on the set of real numbers.

$\lim_{x\rightarrow 5}\frac{4x^2-7x-65}{x^2+10}=\frac{100-35-65}{25+10}=0$

6. $k(x)=\frac{x+1}{x^2+x+29}$

$x^2+x+29=0$

It cannot be factorize .

Therefore, it has no real values for which it is not defined .

Hence, function k is defined for all real values.

$\lim_{x\rightarrow 5}\frac{x+1}{x^2+x+29}=\frac{5+1}{25+5+29}=\frac{6}{59}=0.102$

7. $l(x)=\frac{5x-1}{x^2-9x+8}$

$x^2-9x+8=0$

$x^2-8x-x+8=0$

$x(x-8)-1(x-8)=0$

$(x-8)(x-1)=0$

$x=8,1$

The function is not defined for x=8 and x=1

Hence, function l is not defined for all real values.

8. $m(x)=\frac{x^2+5x-24}{x^2+11}$

The denominator of m is defined for all real values of x.

Therefore, the function m is continuous on the set of real numbers.

$\lim_{x\rightarrow 5}\frac{x^2+5x-24}{x^2+11}=\frac{25+25-24}{25+11}=\frac{26}{36}=\frac{13}{18}=0.722$

g(x)<j(x)<k(x)<f(x)<m(x)<h(x)

6 0

2 years ago