Two trains leave stations 360 miles apart at the same time and travel toward each other. One train travels at 70 miles per hour while the other travels at 80 miles per hour. How long will it take for the two trains to meet?
2 answers:
You need to take 360 and divide that by the speed of the trains combined which equals 2.4 hours. so.... 70 + 80= 150 now divide 360 by 150 and you get 2.4 hours as your answer XD hope this helped!
S=d/t ⇒d=s*t s=speed d=distance t=time The first train : d=x x=70 miles/h*t ⇒ x=70t (1) The second train d=360 miles - x 360 miles - x=80 miles/h*t ⇒360-x=80t ⇒ x=360-80t (2) therefore, with the equations (1) and (2) we have a systeme of equations: x=70t x=360-80t we can solve this system of equations by equalization method. 70t=360-80t 70t+80t=360 150t=360 t=360/150=2.4 (≈2 hour 24 minutes)Answer: the first train meet with the second train in 2 hour 24 minutes.
You might be interested in
Answer:
a. 5.8+5+7.8+4.5=23.1 units (perimeter)
b. 11.55 units, half
Step-by-step explanation:
Hope this helps
Answer:
15550.88
Step-by-step explanation:
the formula for the volume of a cylinder is πr^2(h), so plug in height and radius, and you have the answer.
Answer:
Range: {-1, 0, 2, 4}
Domain: {-3, -2, 0, 1}
Step-by-step explanation:
The range is the set containing all y-coordinates.
The domain is the set containing all x-coordinates.
A coordinate appears only once in each set.
Range: {-1, 0, 2, 4}
Domain: {-3, -2, 0, 1}
Answer:
5m^2
Step-by-step explanation:
Given data
Length of board= 2.50m
Width of board= 2m
The cover need should have the same area as the board
Area= Length*Width
Area= 2.5*2
Area=5m^2
Hence the area of the cover is 5m^2
We have that <span>a triangle’s original dimensions are 24 cm by 40 cm scale factor=2.2 then </span>a triangle’s enlargement dimensions=[scale factor]*original dimensions a triangle’s enlargement dimensions=[2.2]*24------> 52.8 cm a triangle’s enlargement dimensions=[2.2]*40------> 80 cmthe answer is a triangle’s enlargement dimensions will be 52.8 cm by 80 cm