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3 years ago

What is (+,+) reflected over the x axis?

Mathematics

2 answers:

elena55 [62]3 years ago

6 0

Answer:

If a coordinate point that has both positives is reflected over the x axis it goes into the bottom right corner. For example, if (4,4) is reflected over the x axis, it goes over the x axis into the bottom right corner and becomes (+4, -4).

Step-by-step explanation:

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sleet_krkn [62]3 years ago

5 0

Answer:

means the the x-axis is positive and the y-axis is positive so it is located in the first quarter of the cariesian corrdenates

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Someone plz help with dis

Lesechka [4]

Think it’s 16 is the answe e

7 0

3 years ago

Which expression is equivalent to 1/8x- 1/2?

pychu [463]

This is done by factoring. 1/8 is smaller than 1/2, so we can factor a 1/8 out of 1/2. This is what that looks like: $\frac{ \frac{1}{2} }{ \frac{1}{8} }$ , because factoring after all is a form of division. When we divide a fraction by a fraction, we bring the lower fraction up and flip it to multiply, giving us this: $\frac{1}{2} * \frac{8}{1}$ . This of course reduces to 4. So when we factor out 1/8, what we will have then is $\frac{1}{8} (x-4)$ , choice D from above.

6 0

3 years ago

Find the sides, and the value of x and y.

Gelneren [198K]

Answer:

$\huge\boxed{x=15;\ y=4}$

Step-by-step explanation:

Proportion:

$\dfrac{x}{18}=\dfrac{5}{6}\qquad|\text{cross multiply}\\\\(x)(6)=(18)(5)\\\\6x=90\qquad|\text{divide both sides by 6}\\\\\huge\boxed{x=15}$

$\dfrac{y}{5}=\dfrac{12}{x}$

substitute x = 15:

$\dfrac{y}{5}=\dfrac{12:3}{15:3}\\\\\dfrac{y}{5}=\dfrac{4}{5}\qquad|\text{cross multiply}\\\\(y)(5)=(5)(4)\\\\5y=20\qquad|\text{divide both sides by 5}\\\\\huge\boxed{y=4}$

3 0

3 years ago

Write the Expression in standard form by expanding and combining like terms 4(8m-7n) +6(3n-4m)

Elina [12.6K]

Standard for is x × 10 ^I
where,
I = indice
10 > x < 0
you cannot write this is standard form with putting in what they stand for. However you can simplify it -

4(8m-7n) +6(3n-4m)
32m - 28n + 18n - 24m
8m - 10n

but hey I am from England do what we call standard form might be different

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=6y%20-%208%20%2B%202" id="TexFormula1" title="6y - 8 + 2" alt="6y - 8 + 2" align="absmiddle" c

lutik1710 [3]

so it will end up at 6y-6

you need to combine everything that does not have an exponent (example. a, x, y) and you combine the ones that have exponents together. and therefore you get 6y-6 (remember positive and negative signs)

8 0

3 years ago