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____ [38]
3 years ago
9

(3) A boy has 10 pens in a pack. He gives 2 pens to his friend. What fraction of the pack is left? *

Mathematics
1 answer:
Olegator [25]3 years ago
8 0

Answer: \frac{4}{5}

Step-by-step explanation:

10 pens - 2 pens = 8 pens

Write 8 of 10 as a fraction.

You get \frac{8}{10}, right?

Now, simplify 8/10.

You get 4/5.

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Answer:

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Step-by-step explanation:

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3 years ago
Divide: 464 : 46<br> Help me
Studentka2010 [4]

Answer:

10.0

Step-by-step explanation: 464:46

5 0
2 years ago
SMART STUDENT PLEASE NEED GOOD MATH STUDENT​
tangare [24]

Answer:

Therefore 'x' is equal to 65.4°

Step-by-step explanation:

In Right Angle Triangle ABC

∠ B = 90°

AC = Hypotenuse = 12

CB = Adjacent Side = 5

To Find:

∠ C = x

Solution:

In Right Angle Triangle ABC Cosine Identity we have

\cos C = \frac{\textrm{side adjacent to angle C}}{Hypotenuse}\\

Substituting the values we get

\cos C = \dfrac{CB}{AC}=\dfrac{5}{12}

\angle C = \cos^{-1}(0.4166)=65.37=65.4\°

Therefore 'x' is equal to 65.4°

8 0
3 years ago
Does anyone know how to do this?
aksik [14]

Answer:

So basically the answer is where the lines intersect if they do not intersect there is no solution if they are on top of one another it is infinite solutions

Step-by-step explanation:

3 0
3 years ago
You coach a basketball ball team of 12 players; 5 players must be on the floor at all times; Figuring that every player can play
makvit [3.9K]
The function "choose k from n", nCk, is defined as
  nCk = n!/(k!*(n-k)!) . . . . . where "!" indicates the factorial

a) No position sensitivity.
The number of possibilities is the number of ways you can choose 5 players from a roster of 12.
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You can put 792 different teams on the floor.

b) 1 of 2 centers, 2 of 5 guards, 2 of 5 forwards.
The number of possibilities is the product of the number of ways, for each position, you can choose the required number of players from those capable of playing the position.
  (2C1)*(5C2)*(5C2) = 2*10*10 = 200
You can put 200 different teams on the floor.
4 0
3 years ago
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