Mike age is 3 less then twice the age of his brother nuke.
M = Mike's age now
N = Nuke's age now
M = 2N - 3
Ten years ago, four times nuke's age was one more mike's age.
M-10 = Mike's age 10 years ago
N-10 = Muke's age 10 years ago
4(N - 10) = 1 + M -10
what are their present ages
find M and N
substitute M = 2N - 3 into 4(N - 10) = 1 + M -10:
4(N - 10) = 1 + [2N - 3] - 10
4N - 40 = 2N - 12
2N = 28
N = 14
M = 2(14) - 3 = 28 - 3 = 25
Mike is 25 and Nuke is 14.
check:
4(14 - 10) = 4(4) = 16 = 26 -10 = 1 + 25 - 10
Answer:
x8 + 1
Step-by-step explanation:
2/72 = 36
2/36 = 18
2/18 = 9
3/9 = 3
3/3 = 1
so now as you can see we have 3 number which is divided by 2 and 2 numbers which is divided by 3. so it becomes, 3*2√2 = 6√2 is final answer.
um...
Step-by-step explanation:
Answer:
b
Step-by-step explanation:
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