All categories

4 years ago

TRUE OR FALSE If a quadrilateral is a square, then the quadrilateral has four right angles.

Mathematics

1 answer:

sammy [17]4 years ago

4 0

False...........hope this helps

You might be interested in

What's the answer???????

Liula [17]

For question number one:
We know that in similar triangles, corresponding sides are proportional.
In this scenario we have two triangles- one made by a stop sign and a shadow and one by a tree and its shadow.
The side of the triangle that is represented by the shadow of the stop sign is proportional to the side of the larger triangle represented by the shadow of the tree.
Also, the side of the smaller triangle that is represented by the height of the stop sign is proportional to the side of the bigger triangle represented by the height of the tree.
Using this information we can conclude that 12/42=18/h
By cross multiplying: 12h=42(18)
solve for h: (42)(18)/(12)=h
calculate: h=63
The height of the tree is 63 ft.

6 0

3 years ago

What is 920 divided by 30??

Keith_Richards [23]

920/30=92/3=90/3+2/3=30+2/3=30 and 2/3

6 0

4 years ago

What are the unknowns in this problem?

sergij07 [2.7K]

<span>the total number of pens in the container in all
</span>
the total number of markers in the container in all <span>(this one too because it doesnt say anything about markers, but we dont know if there is markers in this or not.)</span>

the total number of pencils in the container in all

3 0

4 years ago

Is .36 equivalent to 10/33

sattari [20]

No.

0.36 = 36/100 =9/25

_____

In decimal form, 10/33 = $0.\overline{30}$ which is not 0.36.

6 0

3 years ago

Determine the above sequence converges or diverges. If the sequence converges determine its limit

marshall27 [118]

Answer:

This series is convergent. The partial sums of this series converge to $\displaystyle \frac{2}{3}$ .

Step-by-step explanation:

The $n$ th partial sum of a series is the sum of its first $n\!\!$ terms. In symbols, if $a_n$ denote the $n\!$ th term of the original series, the $\! n$ th partial sum of this series would be:

$\begin{aligned} S_n &= \sum\limits_{k = 1}^{n} a_k \\ &= a_1 + a_2 + \cdots + a_{k}\end{aligned}$ .

A series is convergent if the limit of its partial sums, $\displaystyle \lim\limits_{n \to \infty} S_{n}$ , exists (should be a finite number.)

In this question, the $n$ th term of this original series is:

$\displaystyle a_{n} = \frac{{(-1)}^{n+1}}{{2}^{n}}$ .

The first thing to notice is the ${(-1)}^{n+1}$ in the expression for the $n$ th term of this series. Because of this expression, signs of consecutive terms of this series would alternate between positive and negative. This series is considered an alternating series.

One useful property of alternating series is that it would be relatively easy to find out if the series is convergent (in other words, whether $\displaystyle \lim\limits_{n \to \infty} S_{n}$ exists.)

If $\lbrace a_n \rbrace$ is an alternating series (signs of consecutive terms alternate,) it would be convergent (that is: the partial sum limit $\displaystyle \lim\limits_{n \to \infty} S_{n}$ exists) as long as $\lim\limits_{n \to \infty} |a_{n}| = 0$ .

For the alternating series in this question, indeed:

$\begin{aligned}\lim\limits_{n \to \infty} |a_n| &= \lim\limits_{n \to \infty} \left|\frac{{(-1)}^{n+1}}{{2}^{n}}\right| = \lim\limits_{n \to \infty} {\left(\frac{1}{2}\right)}^{n} =0\end{aligned}$ .

Therefore, this series is indeed convergent. However, this conclusion doesn't give the exact value of $\displaystyle \lim\limits_{n \to \infty} S_{n}$ . The exact value of that limit needs to be found in other ways.

Notice that $\lbrace a_n \rbrace$ is a geometric series with the first term is $a_0 = (-1)$ while the common ratio is $r = (- 1/ 2)$ . Apply the formula for the sum of geometric series to find an expression for $S_n$ :

$\begin{aligned}S_n &= \frac{a_0 \cdot \left(1 - r^{n}\right)}{1 - r} \\ &= \frac{\displaystyle (-1) \cdot \left(1 - {(-1 / 2)}^{n}\right)}{1 - (-1/2)} \\ &= \frac{-1 + {(-1 / 2)}^{n}}{3/2} = -\frac{2}{3} + \frac{2}{3} \cdot {\left(-\frac{1}{2}\right)}^{n}\end{aligned}$ .

Evaluate the limit $\displaystyle \lim\limits_{n \to \infty} S_{n}$ :

$\begin{aligned} \lim\limits_{n \to \infty} S_{n} &= \lim\limits_{n \to \infty} \left(-\frac{2}{3} + \frac{2}{3} \cdot {\left(-\frac{1}{2}\right)}^{n}\right) \\ &= -\frac{2}{3} + \frac{2}{3} \cdot \underbrace{\lim\limits_{n \to \infty} \left[{\left(-\frac{1}{2}\right)}^{n} \right] }_{0}= -\frac{2}{3}\end{aligned}}_$ .

Therefore, the partial sum of this series converges to $\displaystyle \left(- \frac{2}{3}\right)$ .

8 0

3 years ago