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andreyandreev [35.5K]
3 years ago
12

What is the product?

Mathematics
2 answers:
zepelin [54]3 years ago
8 0

Answer:

Option D

Step-by-step explanation:

We need the product of:

(-3s + 2t)*(4s - t)

We can use the distributive property:

(a + b)*(c + d) = a*c +b*c + a*d + b*d

Applying to our case:

(-3s + 2t)*(4s - t) = (-3s)*4s + (-3s)*(-t) + 2t*4s + (2t)*(-t)

(-3s + 2t)*(4s - t) = -12(s^2) + 3st + 8ts - 2(t^2)

(-3s + 2t)*(4s - t) = -12(s^2) + 11ts - 2(t^2)

So, the correct is option D negative 12 s squared + 11 s t minus 2 t squared

MAXImum [283]3 years ago
8 0

Answer:

Option D

Step-by-step explanation:

I just took the Test On ED

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Y_Kistochka [10]

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Solve the following differential equations or initial value problems. In part (a), leave your answer in implicit form. For parts
shepuryov [24]

Answer:

(a) (y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) y = arctan(t(lnt - 1) + C)

(c) y = -1/ln|0.09(t + 1)²/t|

Step-by-step explanation:

(a) dy/dt = (t^2 + 7)/(y^4 - 4y^3)

Separate the variables

(y^4 - 4y^3)dy = (t^2 + 7)dt

Integrate both sides

(y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) dy/dt = (cos²y)lnt

Separate the variables

dy/cos²y = lnt dt

Integrate both sides

tany = t(lnt - 1) + C

y = arctan(t(lnt - 1) + C)

(c) (t² + t) dy/dt + y² = ty², y(1) = -1

(t² + t) dy/dt = ty² - y²

(t² + t) dy/dt = y²(t - 1)

(t² + t)/(t - 1)dy/dt = y²

Separating the variables

(t - 1)dt/(t² + t) = dy/y²

tdt/(t² + t) - dt/(t² + t) = dy/y²

dt/(t + 1) - dt/(t(t + 1)) = dy/y²

dt/(t + 1) - dt/t + dt/(t + 1) = dy/y²

Integrate both sides

ln(t + 1) - lnt + ln(t + 1) + lnC = -1/y

2ln(t + 1) - lnt + lnC = -1/y

ln|C(t + 1)²/t| = -1/y

y = -1/ln|C(t + 1)²/t|

Apply y(1) = -1

-1 = ln|C(1 + 1)²/1|

-1 = ln(4C)

4C = e^(-1)

C = (1/4)e^(-1) ≈ 0.09

y = -1/ln|0.09(t + 1)²/t|

8 0
4 years ago
Daniel spent $4.75 for lunch and $1.85 for a snack. Kyle spent $5.75 for lunch and $1.00 for a snack. How much more money did Ky
Katena32 [7]
Daniel spent $4.75 for a lunch and $1.85 for a snack
$4.75+$1.85=$6.6, so Daniel spent $6.6 total

Kyle spent $5.75 for lunch and $1.00 for a snack
$5.75+$1.00=$6.75, so Kyle spend total $6.75.

Final step:
$6.75-$6.6=$0.15. As a result, Kyle spent $0.15 or 15 cent more than Daniel. Hope it help!
3 0
4 years ago
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