2 ways to find the y int.
(1) put the equation in y = mx + b form and the y int will be in the b position
7x - 3y = -5
-3y = -7x - 5
y = 7/3x + 5/3....so 5/3 is ur y int
(2) another way is to sub in 0 for x and solve for y
7(0) - 3y = -5
-3y = -5
y = -5/-3
y = 5/3...ur y int
When calculating consecutive integers, the smaller number is x and the larger number is (x + 1).
So the equation you can use is x + (x + 1) = 5 + 3(x + 1)
This is because the sum of the consecutive integers are equal to 5 more than 3 times the larger integer.
Now simplify:
x + (x + 1) = 5 + 3(x + 1)
2x + 1 = 5 + 3(x + 1)
2x + 1 = 5 + 3x + 3
2x + 1 = 3x + 8
Now isolate the variable:
2x + 1 = 3x + 8
Subtract 2x from both sides:
1 = x + 8
Subtract 8 from both side:
-7 = x
x = -7
So the smaller number is -7 and the larger number is -6.
Now check your answer:
-7 + (-7 + 1) = 5 + 3(-7 + 1)
-7 + (-6) = 5 + 3(-7 + 1)
-7 + (-6) = 5 + 3(-7 + 1)
-7 - 6 = 5 + 3(-7 + 1)
-13 = 5 + 3(-7 + 1)
-13 = 5 + 3(-6)
-13 = 5 + (-18)
-13 = 5 - 18
-13 = -13
This works!
So the integers are -7 and -6.
Answer:
input x = - 7
Step-by-step explanation:
A is modelled as y = 5x - 4
B is modelled as y = 3x + 8
We require output of A three times the output of B , then
5x - 4 = 3(3x + 8) ← distribute
5x - 4 = 9x + 24 ( subtract 9x from both sides )
- 4x - 4 = 24 ( add 4 to both sides )
- 4x = 28 ( divide both sides by - 4 )
x = - 7 ← input
Answer:
Option C
Step-by-step explanation:
When you put the write the scenario in an equation, it'll look like
(5q+3)(5q-3) for the new width times the new length
Factor these, and you shall get 25q^2+15q-15q-9. Simplify that into
25q^2-9
