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Pavel [41]
2 years ago
6

How can you use transformations to graph this function? y=3•7-x+2 Explain your steps.

Mathematics
1 answer:
ElenaW [278]2 years ago
5 0

The last two easy transformations involve flipping functions upside down (flipping them around the x-axis), and mirroring them in the y-axis.

The first, flipping upside down, is found by taking the negative of the original function; that is, the rule for this transformation is –f (x).

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What does x equal to in the equation −7x>10
natita [175]

Answer:

Step-by-step explanation:

hello :

−7x>10

multiply by : -1   : 7x < -10

x< -10/7

5 0
2 years ago
Mike purchased 1.35 pounds of steak for $13.50.
AlladinOne [14]

Answer:

y=10x

Step-by-step explanation:

it costs 10 dollars for one pound of steak.

3 0
2 years ago
Read 2 more answers
ASPPPPPP!!!
KiRa [710]
The answer should be b
The other one should be 8
3 0
3 years ago
Charlie cannot remember how much he financed to buy his car. He does remember that his monthly payment is $200. His add-on inter
Mazyrski [523]
First find the total payments
Total paid
200×30=6,000 (this is the future value)

Second use the formula of the future value of annuity ordinary to find the monthly payment.
The formula is
Fv=pmt [(1+r/k)^(n)-1)÷(r/k)]
We need to solve for pmt
PMT=Fv÷[(1+r/k)^(n)-1)÷(r/k)]
PMT monthly payment?
Fv future value 6000
R interest rate 0.09
K compounded monthly 12
N=kt=12×(30months/12months)=30
PMT=6000÷(((1+0.09÷12)^(30)
−1)÷(0.09÷12))
=179.09 (this is the monthly payment)

Now use the formula of the present value of annuity ordinary to find the amount of his loan.
The formula is
Pv=pmt [(1-(1+r/k)^(-n))÷(r/k)]
Pv present value or the amount of his loan?
PMT monthly payment 179.09
R interest rate 0.09
N 30
K compounded monthly 12
Pv=179.09×((1−(1+0.09÷12)^(
−30))÷(0.09÷12))
=4,795.15

The answer is 4795.15
5 0
3 years ago
What is 6900g converted to kg???
stich3 [128]
1000 g=1kg
to convert to kg
1kg/1000g=conversion factor
multiply
6900g times 1kg/1000g
grams cancel
6.9 kg
4 0
3 years ago
Read 2 more answers
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