From january 1 to december 31 of the same year, how many times does the suns perpendicular ray cross the equator

Mathematics

1 answer:

laiz [17]2 years ago

3 0

Twice.

Once at the spring equinox, once at the fall equinox.

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Simplify. 54+4(34−12)2 Enter your answer in the box.

gtnhenbr [62]

Answer:

230

Step-by-step explanation:

54+4×22×2

54+88×2

54+176

230

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2 years ago

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Plz answer it’s easy giving brainliest

MariettaO [177]

What is the name of that type of math

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3 years ago

Choose the option with the proper number of sig figs

marishachu [46]

$\text{ 2 }\times10^8$

Explanation: $\begin{gathered} \text{Given:} \\ \frac{9\text{ }\times10^9}{4.5\text{ }\times10^1} \end{gathered}$

let's break down the expression to get the final result:

$\begin{gathered} \frac{9\text{ }\times10^9}{4.5\text{ }\times10^1}\text{ = }\frac{9}{4.5}\times\text{ }\frac{10^9}{10^1} \\ \frac{9}{4.5}\text{ = }\frac{9\text{ }\times\text{ 10}}{4.5\text{ }\times\text{ 10}}\text{ = }\frac{90}{45} \\ \frac{9}{4.5}\text{ = }2 \\ \\ \frac{10^9}{10^1}\colon\text{ when we divide exponents with same base, } \\ we\text{ take one of the base and combine the exponents by subtracting them:} \\ \frac{10^9}{10^1}=10^{9-1} \\ \frac{10^9}{10^1}=10^8 \end{gathered}$ $\begin{gathered} \frac{9}{4.5}\times\text{ }\frac{10^9}{10^1}\text{ = 2 }\times10^8 \\ \\ \text{when dividing decimals, }the\text{ least number of }significant\text{ }figures\text{ in the problem}, \\ \text{ }\det ermines\text{ the significant figures in the answer} \\ 9\text{ = 1 significant, 4.5 = 2 significant} \\ \text{The least significant is 1} \\ \\ \frac{9\text{ }\times10^9}{4.5\text{ }\times10^1}\text{ = 2 }\times10^8 \end{gathered}$

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8 months ago

HElP pLeAsE 32y + 12y = 44y

BartSMP [9]

Answer:44y=44y

Step-by-step explanation: combine the like terms of 32y and 12y and u get 44y=44y which cant be simplified further

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777dan777 [17]

Answer:

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