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Nimfa-mama [501]
3 years ago
12

Yocum Company purchased equipment on January 1 at a list price of $120,000 and received a $2,400 cash discount. Yocum paid $6,00

0 sales tax on the equipment, and paid installation charges of $1,760. Prior to installation, Yocum paid $4,000 to pour a concrete slab on which to place the equipment. What is the total cost of the new equipment?
Business
1 answer:
egoroff_w [7]3 years ago
8 0

Answer:

The correct answer is $129,360.

Explanation:

According to the scenario, the given data are as follows:

List price of equipment = $120,000

Cash discount = $2,400

sales tax = $6,000

Installation charges = $1,760

concrete slab = $4,000

So, we can calculate the total cost by using following formula:

Total cost = $120,000 - $2,400 + $6,000 +$1,760 + $4,000

= $129,360

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For the first time in two years, Big G (the cereal division of General Mills) raised cereal prices by 4 percent. If, as a result
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b. inelastic

c. Yes - it decreased

Explanation:

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= -2/4 = -0.5

The absolute value is 0.5

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I hope my answer helps you

7 0
3 years ago
Shalit Corporation’s 2008 sales were $12 million. Its 2003 sales were $6 million. a. At what rate have sales been growing? b. Su
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6 0
3 years ago
A manufacturer estimates that its product can be produced at a total cost of C(x) = 50,000 + 100x + x3 dollars. If the manufactu
timofeeve [1]

Answer:

The level of production x that will maximize the profit is: 22,966

Explanation:

C(x) = 50,000 + 100x + x³

R(x) = 3400x

P(x) = R(x) - C(x)

      = 3400x - [50,000 + 100x + x³]

      = 3400x - 50,000 - 100x - x³

      = 3300x - 50,000 - x³   .................... (A)

P'(x) = 3300(1) - 0 - 3x²

       = 3300 - 3x²

At a critical point, P'(x) = 0

∴   0 = 3300 - 3x²

  3x² = 3300

    x² = 1100

     x = ± \sqrt{1100}

P"(x) = -6x

P(\sqrt{1100}) = -6 (\sqrt{1100})   < 0

by second derivative, 'P' max at    x = \sqrt{1100} = 33.17 (rounds)

since x =  \sqrt{1100} ,

recall that P(x) = 3300x - 50,000 - x³ from equation (A)

Therefore, Maximum Profit

P(\sqrt{1100}) = 3300\sqrt{1100} - 50000 - \sqrt{1100} ^{3}

              = 3300(33.17) - 50,000 - 33.17³

              = 109461 -50,000 - 36495.26

              = 22,965.74

Maximum profit is 22,966 to the nearest whole number

5 0
2 years ago
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