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bija089 [108]
3 years ago
9

Which is not equal to the absolute value of -1?

Mathematics
1 answer:
timurjin [86]3 years ago
5 0

Answer:

-2

Step-by-step explanation:

Absolute value is the distance from a number to 0 on the number line, so the number can't be negative, only positive. The absolute value of -1 would be 1, therefore it couldn't be -2, or any other negative numbers.

You might be interested in
Write an equation for the nth term of<br> the arithmetic sequence: <br> 15,28,41 ....
11111nata11111 [884]

Answer:

The equation for the nth term of  the given arithmetic sequence is: \mathbf{a_n=13n+22}

Step-by-step explanation:

We need to write an equation for the nth term of  the arithmetic sequence:

15,28,41 ....

The equation for arithmetic sequence is: a_n=a_1+(n-1)d

Where a_n is the nth term, a_1 is first term and d is common difference

In the given sequence we have:

a₁ = 15

a₂ = 28

We can find common difference using the formula:

a_n=a_1+(n-1)d\\Put\: n=2, a_2=28\: and\: a_1=15\\a_2=a_1+(2-1)d\\28=15+d\\d=28-15\\d=13

So, the common difference d is 13

Now, equation for nth term will be:

a_n=a_1+(n-1)d\\Put\:a_1=15, d=13\\a_n=15+(n-1)13\\Solving:\\a_n=15+13n-13\\a_n=13n+2

So, the equation for the nth term of  the given arithmetic sequence is: \mathbf{a_n=13n+22}

where n=1,2,3..

4 0
3 years ago
2(4^2+10) ? will mark brainliest
Ilia_Sergeevich [38]
\bf 2(4^2+10)\qquad \mathbb{PEMDAS}\implies 2(16+10)\implies 2(26)\implies 52
3 0
3 years ago
Read 2 more answers
27. Dylan bought 3 identical shirts online for a total cost of $71.83 including a flat rate of $7.99 for shipping. Write
Sav [38]

Answer:

71.83

Step-by-step explanation:

3 0
2 years ago
Pls help I will give you 15 points
STALIN [3.7K]

Answer:

Ana still needs to read 1/5 of th journal

8 0
3 years ago
9/20
Stella [2.4K]

<u>Question:</u>

Find the number of real number solutions for the equation. x^2 + 5x + 7 = 0

<u>Answer:</u>

The number of real solutions for the equation x^{2}+5 x+7=0 is zero

<u>Solution:</u>

For a Quadratic Equation of form : a x^{2}+b x+c=0  ---- eqn 1

The solution is x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}  

Now , the given Quadratic Equation is x^{2}+5 x+7=0  ---- eqn 2

On comparing Equation (1) and Equation(2), we get

a = 1 , b = 5 and c = 7

In x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a} , b^2 - 4ac is called the discriminant of the quadratic equation

Its value determines the nature of roots

Now, here are the rules with discriminants:

1) D > 0; there are 2 real solutions in the equation

2) D = 0; there is 1 real solution in the equation

3) D < 0; there are no real solutions in the equation

Now let solve for given equation

D= b^2 - 4ac\\\\D = 5^2 - 4(1)(7)\\\\D = 25 - 28 \\\\D = -3

Since -3 is less than 0, this means that there are 0 real solutions in this equation.

4 0
3 years ago
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