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3 years ago

Which is not equal to the absolute value of -1?

Mathematics

1 answer:

timurjin [86]3 years ago

5 0

Answer:

-2

Step-by-step explanation:

Absolute value is the distance from a number to 0 on the number line, so the number can't be negative, only positive. The absolute value of -1 would be 1, therefore it couldn't be -2, or any other negative numbers.

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Write an equation for the nth term of the arithmetic sequence: 15,28,41 ....

11111nata11111 [884]

Answer:

The equation for the nth term of the given arithmetic sequence is: $\mathbf{a_n=13n+22}$

Step-by-step explanation:

We need to write an equation for the nth term of the arithmetic sequence:

15,28,41 ....

The equation for arithmetic sequence is: $a_n=a_1+(n-1)d$

Where $a_n$ is the nth term, $a_1$ is first term and d is common difference

In the given sequence we have:

a₁ = 15

a₂ = 28

We can find common difference using the formula:

$a_n=a_1+(n-1)d\\Put\: n=2, a_2=28\: and\: a_1=15\\a_2=a_1+(2-1)d\\28=15+d\\d=28-15\\d=13$

So, the common difference d is 13

Now, equation for nth term will be:

$a_n=a_1+(n-1)d\\Put\:a_1=15, d=13\\a_n=15+(n-1)13\\Solving:\\a_n=15+13n-13\\a_n=13n+2$

So, the equation for the nth term of the given arithmetic sequence is: $\mathbf{a_n=13n+22}$

where n=1,2,3..

4 0

3 years ago

2(4^2+10) ? will mark brainliest

Ilia_Sergeevich [38]

$\bf 2(4^2+10)\qquad \mathbb{PEMDAS}\implies 2(16+10)\implies 2(26)\implies 52$

3 0

3 years ago

Read 2 more answers

27. Dylan bought 3 identical shirts online for a total cost of $71.83 including a flat rate of $7.99 for shipping. Write

Sav [38]

Answer:

71.83

Step-by-step explanation:

3 0

2 years ago

Pls help I will give you 15 points

STALIN [3.7K]

Answer:

Ana still needs to read 1/5 of th journal

8 0

3 years ago

9/20

Stella [2.4K]

Question:

Find the number of real number solutions for the equation. x^2 + 5x + 7 = 0

Answer:

The number of real solutions for the equation $x^{2}+5 x+7=0$ is zero

Solution:

For a Quadratic Equation of form : $a x^{2}+b x+c=0$ ---- eqn 1

The solution is $x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Now , the given Quadratic Equation is $x^{2}+5 x+7=0$ ---- eqn 2

On comparing Equation (1) and Equation(2), we get

a = 1 , b = 5 and c = 7

In $x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$ , $b^2 - 4ac$ is called the discriminant of the quadratic equation

Its value determines the nature of roots

Now, here are the rules with discriminants:

1) D > 0; there are 2 real solutions in the equation

2) D = 0; there is 1 real solution in the equation

3) D < 0; there are no real solutions in the equation

Now let solve for given equation

$D= b^2 - 4ac\\\\D = 5^2 - 4(1)(7)\\\\D = 25 - 28 \\\\D = -3$

Since -3 is less than 0, this means that there are 0 real solutions in this equation.

4 0

3 years ago