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sladkih [1.3K]
3 years ago
13

2xy³ if x is 2 y is -3 give how to solve for brainliest :)

Mathematics
2 answers:
Rasek [7]3 years ago
6 0

Answer:

-108

Step-by-step explanation:

2xy^3

x=2

y=-3

plug in

2*(2)*(-3)^3

2*2*(-27)

-108

maxonik [38]3 years ago
5 0

\huge\text{Hey there!}

\large\boxed{\rm{2xy^3}}

\large\boxed{\rm{= 2(2)(-3)^3}}

\large\boxed{\rm{= 4(-3)^3}}

\large\boxed{\rm{= 4(-3)(-3)(-3)}}

\large\boxed{\rm{= -12(9)}}

\large\boxed{\rm{= -108}}

\huge\boxed{\rm{Therefore, your \ answer \  is: -108}}\huge\checkmark

\large\text{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

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3 years ago
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yuradex [85]

Answer:

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Step-by-step explanation:

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2 years ago
Thickness measurements of ancient prehistoric Native American pot shards discovered in a Hopi village are approximately normally
mariarad [96]

Answer:

a) 0.1587 (or 15.87%)

b) 0.0478 (or 4.78%)

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Step-by-step explanation:

Find the following probabilities:

(a) the thickness is less than 3.0 mm

We need to find the area under the Normal curve with a mean of 4.5 mm and a standard deviation of 1.5 mm to the left of 3 mm

<h3>(See picture 1 attached) </h3>

We can do that with the help of a calculator or a spreadsheet.

<em>In Excel use </em>

<em>NORMDIST(3,4.5,1.5,1) </em>

<em>In OpenOffice Calc use  </em>

<em>NORMDIST(3;4.5;1.5;1) </em>

and we get the value 0.1587 (or 15.87%)

(b) the thickness is more than 7.0 mm

Now we need the area to the right of 7 (1 - the area to the left of 7)

<h3>(See picture 2 attached) </h3>

<em>In Excel use </em>

<em>1-NORMDIST(7,4.5,1.5,1)  </em>

<em>In OpenOffice Calc use  </em>

<em>1-NORMDIST(7;4.5;1.5;1) </em>

and we get the value 0.0478 (or 4.78%)

(c) the thickness is between 3.0 mm and 7.0 mm

We are looking for the area between 3 and 7

<h3>(See Picture 3) </h3>

Since the area under the Normal equals 1, we have

Area to the left of 3 + Area between 3 and 7 + Area to the right of 7 = 1

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0.1587 +  Area between 3 and 7 + 0.0478 = 1

and

Area between 3 and 7 = 1 - 0.1587 - 0.0478 = 0.7935 (or 79.35%)

4 0
3 years ago
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