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KATRIN_1 [288]
3 years ago
7

A car race qualifier has 10 participants. How many different ways can the top 6 cars cross the finish line?

Mathematics
1 answer:
sleet_krkn [62]3 years ago
5 0

Answer:

There are 151,200 different ways.

Step-by-step explanation:

For solving this question, we need  the concept of permutation, the permutation gives as the number of ordered arrangement that can be made chosen k elements from a group of n elements. it is calculated as:

\frac{n!}{(n-k)!}

So, in this case, we need to find the number of ways in which 6 top participants from the 10 participants can cross the finish line.

Now, we can replace n by 10 and k by 6 and calculate the number of permutations as:

\frac{10!}{(10-6)!}=151,200

Finally, there are 151,200 different ways in which the top 6 cars can cross the finish line.

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