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3 years ago

11. Tickets to a football game were $5 for

Mathematics

1 answer:

slamgirl [31]3 years ago

4 0

Answer:

The number of children that attended the game was 365

Step-by-step explanation:

Let

x ----> the number of children that attended the game

y ---> the number of adults that attended the game

we know that

$x+y=587$ ----> equation A

$5x+7y=3,379$ ----> equation B

Solve the system by graphing

Remember that the solution of the system is the intersection point both graphs

The solution is the point (365,222)

see the attached figure

therefore

The number of children that attended the game was 365

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Is -5/0 undefined. And why is it or why is it not.

xeze [42]

Yes -5/0 is undefined because having 0 of something means you cannot split that 0 into any number so the answer is undefined.

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3 years ago

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oksian1 [2.3K]

Answer:

Step-by-step explanation:

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3 years ago

If Chad makes $10 per yard and $5 per hour, how much will he make if he works for 8 hours total in 3 yards?

kakasveta [241]

Chad makes $10 per yard, and he makes 3 yards

3 x 10 = 30

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hope this helps

5 0

3 years ago

Read 2 more answers

An investment of $8,000 earns interest at an annual rate of 7% compounded continuously. Complete parts (A) and (B) below. Click

Sergeeva-Olga [200]

Answer:

A. $\mathtt{\dfrac{dA}{dt}|_{t=2}=644.15}$

B. $\mathtt{\dfrac{dA}{dt}|_{t = 5.79}= 839.86 }$

Step-by-step explanation:

Given that:

An investment of Amount = $8000

earns at an annual rate of interest = 7% = 0.07 compounded continuously

The objective is to :

A) Find the instantaneous rate of change of the amount in the account after 2 year(s).

we all know that:

$A = Pe^{rt}$

where;

$A = (8000) \ e ^{0.7t}$

The instantaneous rate of change = $\dfrac{dA}{dt}$

$\dfrac{dA}{dt} = \dfrac{d}{dt}(8000 \ e ^{0.07t} )$

$= 8000 \dfrac{d}{dt}e^{0.07 \ t}$

$\dfrac{dA}{dt}= 8000 (0.07)e^{0.07 \ t}$

$\dfrac{dA}{dt}= 560 e^{0.07 \ t}$

At t = 2 years; the instantaneous rate of change is:

$\dfrac{dA}{dt}|_{t=2}= 560 e^{0.07 \times 2}$

$\mathtt{\dfrac{dA}{dt}|_{t=2}=644.15}$

(B) Find the instantaneous rate of change of the amount in the account at the time the amount is equal to $12,000.

Here the amount = 12000

$12000 = (8000)e^{0.07 \ t}$

$\dfrac{12000 }{8000}= e^{0.07 \ t}$

$1.5= e^{0.07 \ t}$

㏑(1.5) = 0.07 t

0.405465 = 0.07 t

t = 0.405465 /0.07

t = 5.79

$\dfrac{dA}{dt}= 560 e^{0.07 \ t}$

At t = 5.79

$\dfrac{dA}{dt}|_{t = 5.79}= 560 e^{0.07 \times 5.79}$

$\mathtt{\dfrac{dA}{dt}|_{t = 5.79}= 839.86 }$

7 0

3 years ago

2. State two (2) values of θ (theta) to the nearest degree for<br> sin θ = − 0. 966

emmasim [6.3K]

Using equivalent angles, the solutions to the equation are given as follows:

$\theta = 255^\circ, \theta = 285^\circ$

<h3>What are equivalent angles?</h3>

Each angle on the second, third and fourth quadrants will have an equivalent on the first quadrant.

In this problem, the equation is:

$\sin{\theta} = -0.966$

Applying the inverse relation:

$\theta = \arcsin{-0.966} = 255^\circ$

Which is on the third quadrant. The equivalent angle on the fourth quadrant is given as follows:

$270^\circ + (270^\circ - 255^\circ) = 285^\circ$

More can be learned about equivalent angles at brainly.com/question/28025397

#SPJ1

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2 years ago