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Mila [183]
3 years ago
6

What is an equivalent expression for 2 Log (sub 4) 3 + Log (sub 4) 2?

Mathematics
1 answer:
Blizzard [7]3 years ago
5 0
Please check the photo for steps and details. Let me know if I was helpful by giving a like and marking brainliest!

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Can you help me. What is 2x-14
mylen [45]

Answer: 2(x-7)

Step-by-step explanation: 2x−14

2x−14

=2(x−7)

4 0
3 years ago
Read 2 more answers
A student desk has an area of 15/16 square meters. The width of the desk is 5/4 meters. What is the length of the desk in meters
olga_2 [115]
For this case, the first thing we are going to do is model the desk as a rectangle.
 The area of the rectangle is given by:
 A = w * l
 Where,
 w: width
 l: length
 Clearing we have:
 l = A / w
 Substituting values:
 l = (15/16) / (5/4)
 Rewriting we have:
 l = (15/16) * (4/5)
 Simplifying we have:
 l = (3/4) m
 Answer:
 
The length of the desk in meters is:
 
l = (3/4) m
7 0
3 years ago
A. 6 square root 2 - 5 square root 2<br><br> b. square root 11 + 3 square root 11
zlopas [31]

Step-by-step explanation:

Number A

= 6√2 - 5√2

= (6 - 5)√2

= √2

Number B

= √11 + 3√11

= (1 + 3)√11

= 4√11

7 0
2 years ago
For which pairs of functions is (f circle g) (x) = 12 x?
nekit [7.7K]

Answer:

its the last answer my boi

Step-by-step explanation:

my big brain

nah i just took the test lol

9 0
3 years ago
PLEASE HELP ASAP: TRIGONOMETRY
ratelena [41]

Recall that sine is the ratio of opposite over hypotenuse, so we say

sin(theta) = opposite/hypotenuse

If we have a triangle labeled as such in the diagram below, then we can use symbols to write sin(theta) = A/C

Similarly, cos(theta) = B/C since cosine is the ratio of adjacent over hypotenuse.

Then from here we use a bit of algebra to compute the left hand side of the given equation. The goal is to see if we can simplify it to 1.

\sin^2\left(\theta\right)+\cos^2\left(\theta\right)\\\\\left(\sin\left(\theta\right)\right)^2+\left(\cos\left(\theta\right)\right)^2\\\\\left(\frac{A}{C}\right)^2+\left(\frac{B}{C}\right)^2\\\\\frac{A^2}{C^2}+\frac{B^2}{C^2}\\\\\frac{A^2+B^2}{C^2}\\\\\frac{C^2}{C^2}\\\\1

So this shows that the left hand side is identically the same as the right hand side (both sides are 1), and it doesn't matter what you replace theta with. Theta can be any real number and the equation will always be true.

Note: if you're wondering how A^2+B^2 became C^2, it's because of the pythagorean theorem. So that's why this trig identity is often referred to as the pythagorean trig identity.

6 0
3 years ago
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