Ask question

Ask question

All categories

4 years ago

8

Find the value of x 6x-10 6x+10

1 answer:

faltersainse [42]4 years ago

5 0

Answer:

total there are 3 values of x as +5/3, -5/3 and 0

Step-by-step explanation:

the given equation is

x(6x-10) (6x+10)=0

this equation can be solved as following

=0 using the formula (a+b)*(a-b)= (a^2-b^2)

here a=6x and b=10

from here we can write either x=0 or 36x^2= 100

or x^2= 100/36 and x=0

or x= ±10/6 and x=0

therefore, total there are 3 values of x as +5/3, -5/3 and 0

You might be interested in

I need some math help please

Yakvenalex [24]

Answer:

A

Step-by-step explanation:

7 0

2 years ago

Convert 5,628,457 to scientific notation

Oliga [24]

Answer:

5.628547 x 10 to the 6th power

7 0

4 years ago

What are the zeros of the quadratic function f(x) = 2x2 + 8x – 3? x = –2 – StartRoot StartFraction 11 Over 2 EndFraction EndRoot

Phantasy [73]

Answer:

The zeros are

$x=-2+\frac{\sqrt{22}}{2}$

$x=-2-\frac{\sqrt{22}}{2}$

Step-by-step explanation:

we have

$f(x)=2x^{2}+8x-3$

we know that

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

Equate the function to zero

$2x^{2} +8x-3=0$

so

$a=2\\b=8\\c=-3$

substitute in the formula

$x=\frac{-8\pm\sqrt{8^{2}-4(2)(-3)}} {2(2)}$

$x=\frac{-8\pm\sqrt{88}} {4}$

$x=\frac{-8\pm2\sqrt{22}} {4}$

$x=-2\pm\frac{\sqrt{22}}{2}$

therefore

$x=-2+\frac{\sqrt{22}}{2}$

$x=-2-\frac{\sqrt{22}}{2}$

4 0

4 years ago

Read 2 more answers

In a half-time skills contest Addison received $5 for each free throw she made and $10 for each 3- point shot. She earned a tota

V125BC [204]

Answer:

o.o

Step-by-step explanation:

4 0

3 years ago

80 kg decreased by 63%

Alina [70]

63% decrease.

0.63•80=50.4kg
80kg-50.4kg=29.6kg

8 0

3 years ago