Question

One ninth divided into nine sixths equal what and reduce to lowest term

Answer 1

$\frac{ \frac{1}{9} }{ \frac{9}{6} }$
You transform it to a multiplication by multiplying the first term (in this case 1/9) by the inverse of the second term (which is in this case 9/6, his inverse is 6/9)
so we get 
$\frac{1}{9}* \frac{6}{9} \frac{6}{81}$
then you divide each number by 3, So we get
$\frac{2}{27}$
Hope this Helps :)

Answer 2

$\rm \frac{ \frac{1}{9}}{ \frac{9}{6} }= \frac{1}{9}* \frac{6}{9}= \frac{6}{81}^{(3}=\boxed{\rm\frac{2}{27} }$