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S_A_V [24]
3 years ago
14

A box contains 6 red marbles, 4 green marbles, 3 blue marbles, and 2 yellow marbles. If Greg chooses one marble at random 300 ti

mes, how many times would he expect the marble to be blue?
Mathematics
1 answer:
dusya [7]3 years ago
3 0

Answer:

60 times

Step-by-step explanation:

There are 6+4+3+2=15 marbles in total. Out of those, 3 are blue, so the probability of pulling a blue marble is \frac{3}{15}=\frac{1}{5}. However, this is only the probability of pulling a blue marble when 1 marble is pulled at random. Therefore, we can expect a blue marble to be pulled \frac{1}{5}*300=60 times if 1 marble is pulled 300 times at random. Hope this helps!

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5 0
3 years ago
2^n-5×5^n-4=5
Papessa [141]

\huge{\fbox{\sf{n=5 }}}

Step 1:

⇒ {2}^{n - 5}   \times  {5}^{n - 4}  = 5

Step 2:

⇒{2}^{n - 5}  \times  {5}^{n - 4}  =  {5}^{1}  \times  {2}^{0}

On comparing values we get:

Taking:

{2}^{n - 5}  =  {2}^{0}

n-5=0

n=5✓

or

Taking:

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3 0
3 years ago
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Strike441 [17]
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A and B counters = 36
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Since we already know A and B we can subtract them from 63 to get C
C= 63- 36 = 27
Now we have to find A by looking for what number gives us the difference of 10 when subtracted from C.
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18 and 18 wont work because it does not give us the difference of 10.
So A = 17 counters and B = 19 counters.

3 0
3 years ago
Let f(x) = 4x+3 and g(x) = -2x +5. Find (f o g)(5)
Sergio [31]
G(5) = -2(5) + 5  = -5

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8 0
3 years ago
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