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S_A_V [24]
3 years ago
14

A box contains 6 red marbles, 4 green marbles, 3 blue marbles, and 2 yellow marbles. If Greg chooses one marble at random 300 ti

mes, how many times would he expect the marble to be blue?
Mathematics
1 answer:
dusya [7]3 years ago
3 0

Answer:

60 times

Step-by-step explanation:

There are 6+4+3+2=15 marbles in total. Out of those, 3 are blue, so the probability of pulling a blue marble is \frac{3}{15}=\frac{1}{5}. However, this is only the probability of pulling a blue marble when 1 marble is pulled at random. Therefore, we can expect a blue marble to be pulled \frac{1}{5}*300=60 times if 1 marble is pulled 300 times at random. Hope this helps!

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For questions 4-5, decide whether each table of values describes a function or not.
lara31 [8.8K]

Answer:

Function

Step-by-step explanation:

Two different X's could equal the same Y value so this is a function. Remember if there's multiple of the same input (x) equalling different outputs (y) then it is not a function. If there's multiple inputs (x) equalling the same output (y) it's just coincidence and works.

3 0
3 years ago
A small pebble has a mass of<br> about<br> 20 L<br> b.<br> 20 ml<br> 20 g<br> 20 kg<br> d.
zhuklara [117]

Answer:

20g

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7 0
3 years ago
Nathaniel was given a large box of 24 chocolates for his birthday. If he
Alik [6]
24 - (2 x 8)
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7 0
3 years ago
Law of cosines <br><br> HELP MES
Lorico [155]

Answer:

70.52 degrees

Step-by-step explanation:

To find the angles, we must first find the lengths of each side of the triangle. Adding up the respective radii, we can see that

XY = 5+4 = 9 CM

XZ = 6+5 = 11 CM

ZY = 4+6 = 10 CM

Now we can apply the cosine rule

C\:=\:\sqrt{A^2+B^2-2ABcosx}

We need to rearrange the rule to solve for x, our missing angle

x\:=\:cos^{-1}\left(\frac{a^2+b^2-c^2}{2ab}\right)

solving for our unknown angle:

x\:=\:cos^{-1}\left(\frac{9^2+10^2-11^2}{2\cdot 9\cdot 10}\right)

x\:=\:70.52^{\circ }

Therefore angle YXZ is 70.52 degrees

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