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Zarrin [17]
4 years ago
7

Which inequalities would have an open circle when graphed? Check all that apply.

Mathematics
2 answers:
kolbaska11 [484]4 years ago
6 0

It is given that the inequalities.

We need to determine the inequalities which have an open circle.

The graph will have an open circle only if it has the symbol < or > because it indicates that the boundary is not included.

<u>Option A</u>: t \geq 25

The inequality shows that it contains the boundary point 25.

Hence, the inequality t \geq 25 does not have an open circle.

Hence, Option A is not the correct answer.

<u>Option B</u>: -2.5 \leq m

The inequality shows that it contains the boundary point -2.5.

Hence, the inequality -2.5 \leq m does not have an open circle.

Hence, Option B is not the correct answer.

<u>Option C</u>: x>5.4

The inequality shows that it does not contains the boundary point 5.4

Hence, the inequality x>5.4 have an open circle.

Thus, Option C is the correct answer.

<u>Option D</u>: \frac{1}{2}>x

The inequality shows that it does not contain the boundary point \frac{1}{2}

Hence, the inequality \frac{1}{2}>x have an open circle.

Thus, Option D is the correct answer.

<u>Option E</u>: x>0

The inequality shows that it does not contain the boundary point 0

Hence, the inequality x>0 have an open circle.

Thus, Option E is the correct answer.

Fofino [41]4 years ago
6 0

Answer:

x > 5.4

One-half less-than x

x > 0

these are correct C D E

Step-by-step explanation:

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