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3 years ago

Suppose S is between R and T. Use the Segment Addition Postulate to solve for z.. RS=2z+6, ST=4z−3, RT=5z+12

Mathematics

1 answer:

Lynna [10]3 years ago

7 0

Answer:

Step-by-step explanation:

If S is between R and T, then RS+ST = RT

Given the following parameters

RS=2z+6,

ST=4z−3,

RT=5z+12

On substituting

2z+6+4z-3 = 5z+12

Collect like terms

2z+4z-5z = 12+3-6

6z-5z = 15-6

z = 9

Hence the value of z is 9

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Given the universal set U

Oxana [17]

Answer:

Step-by-step explanation:

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3 years ago

What is the area of rhombus ABCD? Enter your answer in the box. Do not round at any steps. put the answer in units²

AlladinOne [14]

Answer:

Therefore the Area of Rhombus ABCD is 36 unit².

Step-by-step explanation:

Given:

ABCD is a Rhombus

A = (-1,0)

B = (5,-3)

C = (-1,-6)

D = (-7 ,-3)

To Find:

Area of Rhombus ABCD = ?

Solution:

We know that Area of Rhombus is given as

$\textrm{Area of Rhombus}=\dfrac{1}{2}\times d_{1}\times d_{2}$

Where ,

d₁ and d₂ are the Diagonals.

We have,

Diagonals as AC and BD,

Using Distance Formula we get

$l(AC) = \sqrt{((x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} )}$

Substituting coordinates A and C we get

$l(AC) = \sqrt{((-1-(-1))^{2}+(-6-0)^{2} )}=\sqrt{36}\\l(AC)=6\ unit$

Similarly for BD we have,

$l(BD) = \sqrt{((5-(-7))^{2}+(-3-(-3))^{2} )}=\sqrt{144}\\l(BD)=12\ unit$

Now Substituting AC and BD in Formula we get

$\textrm{Area of Rhombus}=\dfrac{1}{2}\times AC\times BD$

$\textrm{Area of Rhombus}=\dfrac{1}{2}\times 6\times 12=36\ unit^{2}$

Therefore the Area of Rhombus ABCD is 36 unit².

6 0

2 years ago

What is 30-20-65+10+4=

ryzh [129]

Answer:

-41

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

If f(x)=4(3x-5), find f^-1(x)

Margaret [11]

Answer:

f^-1(x) = (x+20) / 12

Step-by-step explanation:

f(x) = 4(3x-5)

Let y be the image of f.

y = 4(3x-5)

y = 12x-20

y+20 = 12x

x = (y+20) / 12

f^-1(y) = (y+20) / 12, so

f^-1(x) = (x+20) / 12

3 0

2 years ago

David went to a fast-food shop for a meal in a late evening. Only steak, pork chop and grilled chicken were available for main c

Doss [256]

six

Step-by-step explanation:

the reason is this: let steak be (s), pork be (p), grilled chicken be (gc), tea be (t), and coffee be (c)

now, we want to find the total number of outcomes, and this cannot be determined by a simple roll of the dice. you have to count the sample space required for EVERY outcome, and it has to lie within the conditions. so, assuming David only takes 1 main course and 1 drink, he would be down to six option, which are :

1. s & t

2. s & c

3. p & t

4. p & c

5. gc & t

6. gc & c

5 0

2 years ago